How would you lift 1kG 20CM in joules?

Answer 1

We'll reformulate the question in this answer. First let's define the terms.

E = F*s, energy is the force times the displacement.

1 J = 1 N m; J (joule) is the unit of energy, N (Newton) is the unit of force, m (meter) is the unit of displacement.

F = m*a, force is mass times accelleration

1 N = 1 kg m / s^2, kg (kilogram) is the unit of mass, s (second) is the unit of time.

The question assumes being on earth and asks:

How much energy does it cost to lift 1 kg over a height of 20 cm = 0.2 m.

Let's call the force of gravity F_g, the height h, the gravity accelleration g. Then our formula for gravity energy becomes:

E_g = F_g * h = (m * g) * h

In this example,

m = 1 kg, h = 0.2 m and g = -9.8 m / s^2 (approximately)

For the value of g, Google it, use a table or do your own experiments :-).

The negative sign in g means that the gravity is opposite to the movement. Positive energy means that it gives energy, negative energy means that it costs energy.

Substituting the values gives

E_g = 1 * 0.2 * -9.8 kg m / s^2 = - 0.49 J,

hence, it costs 0.49 J to lift 1 kg 20 cm.

Answer 2

To lift 1kg by 20cm, you need to calculate the potential energy. The formula to determine potential energy is PE = mgh, where m is the mass (1kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height (0.20m). Plugging in the values, you would find that the potential energy required to lift 1kg by 20cm is approximately 1.96 joules.