39 seconds
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/s²), assuming the ball is dropped and not thrown.
After each bounce, the ball reaches half of the height from which it was dropped. Since the ball was initially dropped from 10 feet, on the first bounce it will reach 5 feet, on the second bounce it will reach 2.5 feet, on the third bounce it will reach 1.25 feet, and on the fourth bounce it will reach 0.625 feet.
A tennis ball typically bounces to about 50-60% of the height it was dropped from. So, if dropped from 5 feet onto asphalt, it would bounce back up to around 2.5 to 3 feet. The actual height can vary depending on factors like the ball's pressure, surface condition, and angle of impact.
The time it takes for the ball to reach the ground can be calculated using the formula ( t = \sqrt{\frac{2h}{g}} ), where ( h = 64 , \text{feet} ) is the initial height of the ball and ( g = 32 , \text{ft/s}^2 ) is the acceleration due to gravity. Substituting the values, the time taken for the ball to reach the ground is ( t = \sqrt{\frac{2 \times 64}{32}} = \sqrt{4} = 2 , \text{seconds} ).
A super ball can bounce up to around 90% of its drop height, so if it is dropped from 5 feet, it could potentially bounce back up to around 4.5 feet. However, this can vary based on factors like the surface it bounces on and the initial impact angle.
If the ball was dropped from a roof and hit the ground 3.03 seconds later, then when it hit the groundits velocity was 29.694 meters (97.42 feet) per second (rounded) downward.
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/s²), assuming the ball is dropped and not thrown.
1.364 seconds to travel 50 feet at 25mph.
Ignoring air resistance (which probably is not safe to do) it would impact at a smidge over 18 seconds from when it was released and be traveling about 580 feet per second.
a. 144 feet b. 96 ft/sec.
No, it would hit slower because gravity on the moon is 1/6 the gravity on earth.
After each bounce, the ball reaches half of the height from which it was dropped. Since the ball was initially dropped from 10 feet, on the first bounce it will reach 5 feet, on the second bounce it will reach 2.5 feet, on the third bounce it will reach 1.25 feet, and on the fourth bounce it will reach 0.625 feet.
If it takes 78 seconds to go 55 feet you are traveling at 0.48 miles per hour.
whats the weight and shape of the rock it depends on that >:(
5.87 seconds.
34.5 feet
it depense what kind of serface it is but if its hard it will go from 6 to 7 feet