If you dcrease the temperature you will decrease the pressure proportionately. So, T1 over T2 will equal P1 over P2. We can derive the formula P1 x T2 = P2 x T1. Substitue the values and we get 50.0 mm x 200K = P2 x 540K 10,000 mmK = P2 x 540K 10,000mmK / 540K = P2 P2 = 18.52 mm of Mercury in a constant volume
25lb/in^2
If the gas behaves as a perfect gas, it obeys Boyle's Law, which can be stated as 'at constant temperature, pressure is inversely proportional to volume'. In this case the pressure is multiplied by 5/2, so the volume will be 2/5 of the original, i.e. 2 l.
density = mass / volumeso 0.78 (lbs/gal) = 500 lbs / volume (gal)500/0.78 = volume = 641.03 gallons
About 240 psi at 500 feet of depth.
1 gram = 1 mL so;500 g = 500 mL34
500. mmHg
400 mL (Explanation): again boyle's law PV=PV. Since the pressure is halved (500 to 250), then the volume must be doubled in order to maintain this equation. 200 x2=400 so that's the answer
p1.V1 / T1 = constant = p2.V2 / T2 (the 'Boyle&Gay-Lussac' Law)250*15/100 = 500*30/ T2T2 = 400K
25lb/in^2
500 cubic centimeters is the volume in this case.
V = k*T/P Apart from the fact that a change in temperature from 20C to 80C cannot be described as a reduction, V2 = V1 * T2P1/T1P2 = 500*(273.15+80)*420/[(273.15+20)*650] = 500*353.15*420/(293.15*650) = 289.2 mL
If the gas behaves as a perfect gas, it obeys Boyle's Law, which can be stated as 'at constant temperature, pressure is inversely proportional to volume'. In this case the pressure is multiplied by 5/2, so the volume will be 2/5 of the original, i.e. 2 l.
2gallons
The volume is 5m3 density=1,200 kgm3 what is the mass
Nothing can have a volume of 500 cm. Volume cannot be measured in cm, which is a measure of length - in 1D space, not volume in 3D space.
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