40.3kg = 6.3 stone
That depends what substance you have.
If it's air, the density is very small.
If it's granite, the density is very large.
It doesn't even matter how much of it you have.
The density is the same for any amount.
All that matters is what the substance is.
40 grams = 1.411 ounces.
They both have the same mass, however their weight is different. Since the 40 g rock has more density it would have more weight.
There are 1000 grams in one kilogram. Therefore, 40000 grams is equal to 40000/1000 = 40 kilograms.
40 kilograms is a weight equal to about 88.2 pounds.
This cannot be sensibly answered. A milliliter (mL or ml) is a measure of volume, grams is a measure of weight or mass.
40 liter= 40/1000 kiloliter =0.04 kiloliters
They both have the same mass, however their weight is different. Since the 40 g rock has more density it would have more weight.
The mass of 40 grams is 40 grams and the volume of 20mL is, wait for it, ... 20 mL!
This is not a valid conversion; milligrams (mg) and grams (g) are measures of weight or mass while milliliters (mL or ml) measure volume.
what is 45 kilograms in stone weight
40 grams
This cannot be sensibly answered. A milliliter (mL or ml) is a measure of volume, grams (g), kilograms (kg) and milligrams (mg) are measures of weight or mass.
1 ounce is equal to 28,34952 g.So 40g is equivalent to 1,411 ounces.
First take the weight in pounds and multiply it by 453.59. The resulting number is the weight in grams. In this case the answer is 18144 grams.
There are approximately 29.57 grams per ounce. To put it differently, there are 0.0338 ounces per gram. Therefore, the weight in grams for 40 oz is approximately 1182.94.
There are 1000 grams in one kilogram. Therefore, 40000 grams is equal to 40000/1000 = 40 kilograms.
Just add the two masses: 40 + 120 = 160 grams.
Na + O + H = ? 22.99 +16.00+1.01= 40 this is easily found with any compound, just add their molar masses up. If there are elements that are present which you have more than one of just multiply its mass by that number.