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You use the equation d = vit + 1/2at2, where d is distance or displacement, vi is initial velocity (0), t is time, and a is acceleration.

d = (0)(10s) + (1/2)(9.8m/s2)(10s)2 = 0 + 490m = 490m

The answer above does not take into account air friction or the possibility that the rock will hit the walls of the shaft and slow down due to that friction.

Air friction will shorten the distance by perhaps 15% to 30% depending, among other things on the shape and mass of the rock, retardation due to hitting the shaft walls is unpredictable.

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Related Questions

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