answersLogoWhite

0

The work done by the person on the box can be calculated using the formula: Work = Force x Distance. In this case, the person applies a force of 200N over a distance of 5 meters. Thus, the work done is 200N x 5m = 1000 Joules.

User Avatar

AnswerBot

1y ago

What else can I help you with?

Continue Learning about Physics

If Chris Bromham took off on his Yamaha and jumped a horizontal distance of 74.0 m across a row of cars and assuming that he started and landed at the same level and was airborne for 1.3 s, what was his initial (angled) velocity as he left the ground?

To find Chris Bromham's initial velocity when he left the ground, you can use the horizontal distance he traveled, the time he was in the air, and the acceleration due to gravity. The equation to use is: horizontal distance = horizontal velocity * time in the air. By rearranging the equation to solve for the horizontal velocity, you can find Chris Bromham's initial velocity when he left the ground.


Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0 and Acirc and deg. If the ball moves through the air for 3.2 seconds what is the horizontal distance tr?

Oh, dude, let me break it down for you. So, Norma kicks the ball at 10.0 m/s at 30 degrees. The horizontal distance the ball travels can be calculated using the formula: distance = velocity * time. Just plug in the numbers and solve for the horizontal distance. It's like a piece of cake, man.


What plane of motion is horizontal extension in?

Horizontal extension is in the transverse plane of motion, which runs horizontally across the body from side to side. This movement involves extending the arms or legs outwards away from the midline of the body.


Is diameter the distance around an object?

No, the diameter is the distance across a circle passing through its center. The distance around a circle is called the circumference.


An adult pulls a child 350-meters across the snow on a sled. They exert a force of 25 newtons at an angle of 30.0 Deg above the horizontal to pull the rope attached to the sled. What is the force?

The horizontal component of the force is given by 25 * cos(30°), which is approximately 21.65 N. This is the force that is responsible for pulling the sled across the snow.