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What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency?

The kinetic energy of the emitted electrons can be calculated using the formula: ( KE = hf - \phi ), where ( KE ) is the kinetic energy, ( h ) is Planck's constant, ( f ) is the frequency of the UV rays, and ( \phi ) is the work function of cesium.


If molybdenum is irradiated with light of a wavelength of 122 nm what is the maximum possible kinetic energy of the emitted electrons?

The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.


How to calculate the work function of a material?

To calculate the work function of a material, you can use the equation: Work Function Planck's constant x Frequency of incident light - Kinetic energy of emitted electrons This formula takes into account the energy required to remove an electron from the material's surface. The work function is typically measured in electron volts (eV).


How do you calculate kinetic energy of the photoelectron emitted from the surface?

To calculate the kinetic energy of a photoelectron emitted from a surface, you can use the equation: ( KE = hf - \phi ), where ( KE ) is the kinetic energy of the photoelectron, ( h ) is the Planck constant, ( f ) is the frequency of the incident photon, and ( \phi ) is the work function of the material.


How does an increase in the intensity affect the maximum kinetic energy of the photoelectrons?

An increase in the intensity of light does not affect the maximum kinetic energy of photoelectrons. The maximum kinetic energy of photoelectrons is determined by the frequency of the incident light, according to the photoelectric effect equation E = hf - φ, where f is the frequency of the light and φ is the work function of the material.

Related Questions

What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency?

The kinetic energy of the emitted electrons can be calculated using the formula: ( KE = hf - \phi ), where ( KE ) is the kinetic energy, ( h ) is Planck's constant, ( f ) is the frequency of the UV rays, and ( \phi ) is the work function of cesium.


If molybdenum is irradiated with light of a wavelength of 122 nm what is the maximum possible kinetic energy of the emitted electrons?

The maximum kinetic energy of the emitted electrons is calculated using the formula: (E_k = hf - \phi), where (h) is the Planck constant, (f) is the frequency of the light (speed of light/wavelength), and (\phi) is the work function of molybdenum. Given the wavelength, you can calculate the frequency, then use the work function value for molybdenum to find the maximum kinetic energy of the emitted electrons.


How to calculate the work function of a material?

To calculate the work function of a material, you can use the equation: Work Function Planck's constant x Frequency of incident light - Kinetic energy of emitted electrons This formula takes into account the energy required to remove an electron from the material's surface. The work function is typically measured in electron volts (eV).


In the Photoelectric effect after the threshold frequency what effect does the increased frequency have on the photocurrent If you assume the Intensity of the source to be constant?

The increased frequency increases the kinetic energy of the single electron ejected. Remember that the incident light releases a single electron when the threashod frequency is reached


How do you calculate kinetic energy of the photoelectron emitted from the surface?

To calculate the kinetic energy of a photoelectron emitted from a surface, you can use the equation: ( KE = hf - \phi ), where ( KE ) is the kinetic energy of the photoelectron, ( h ) is the Planck constant, ( f ) is the frequency of the incident photon, and ( \phi ) is the work function of the material.


How does an increase in the intensity affect the maximum kinetic energy of the photoelectrons?

An increase in the intensity of light does not affect the maximum kinetic energy of photoelectrons. The maximum kinetic energy of photoelectrons is determined by the frequency of the incident light, according to the photoelectric effect equation E = hf - φ, where f is the frequency of the light and φ is the work function of the material.


Why the kinetic energy of the emitted electrons varies up to a maximum value?

Let the work function of a metal be W. Let C be a constant of the dimension of energy. if Kis the maximum kinetic energy of an electron then.......W=C-K..... (K HERE IS THE ENERGY SUPLIED BY A PHOTON TO THE ELECTRON)


What is the difference between work function and threshold frequency?

Oh, dude, work function and threshold frequency are like distant cousins at a family reunion. Work function is the minimum energy needed to eject an electron from a metal surface, while threshold frequency is the minimum frequency of light required to cause photoelectric emission. So, like, work function is about energy, and threshold frequency is about frequency. They're related, but not like, best friends or anything.


What is the relationship between the kinetic energy of a photoelectron and the frequency of the incident light in the photoelectric effect?

In the photoelectric effect, the kinetic energy of a photoelectron is directly proportional to the frequency of the incident light. This means that higher frequency light will result in photoelectrons with greater kinetic energy.


How is energy in potential and kinetic conserved?

For any object, the summation of its potential and kinetic energies is constant.


What is the frequency of the ke of a body in shm if the time period of shm is t?

The frequency of the kinetic energy of a body in simple harmonic motion (SHM) is double the frequency of the oscillations. Therefore, the frequency of the kinetic energy is 1/T, where T is the time period of the SHM.


What happens to the kinetic energy when you increase the speed but keep the mass constant?

When you increase the speed while keeping mass constant, the kinetic energy increases. Kinetic energy is directly proportional to the square of the velocity, so as speed increases, kinetic energy increases even more rapidly.