Starting and ending poInt
The ratio of the distance covered to the displacement of a particle moved along a semi-circle of radius r is π. This is because the distance covered around the semi-circle is the circumference (2πr), while the displacement is the diameter of the circle (2r). The ratio is therefore (2πr) / (2r) = π.
No. Displacement is how far an object is from its original position. This means that if an object traveled in a circle and returned to its original point, it will have a displacement of 0 while the distance will be whatever the circumference of the circle was. Hope that helps.
the distance is obtained by knowing the perimeter of the circle in question, this Canberra determined using the rule for circle circunfrence. As for the displacement it is the shortest distance between the starting pint of travel and ending. If for example the vehicle traveled around the whole circunfrence of a circle it will have a displacement of zero, as for it's distance it will be the length or circunfrence of the circle.
Sure. As one car goes around a circle and as it completes one full rotation, then distance covered by the car is the circumference of the circle. But the displacement is Zero. So distance but no displacement.
No, displacement cannot be greater than distance. Displacement represents the straight-line distance between the initial and final positions of an object, while distance is the total length of the path traveled. Since displacement is the shortest distance between two points, it cannot be greater than the total distance traveled.
The ratio of the distance covered to the displacement of a particle moved along a semi-circle of radius r is π. This is because the distance covered around the semi-circle is the circumference (2πr), while the displacement is the diameter of the circle (2r). The ratio is therefore (2πr) / (2r) = π.
No. Displacement is how far an object is from its original position. This means that if an object traveled in a circle and returned to its original point, it will have a displacement of 0 while the distance will be whatever the circumference of the circle was. Hope that helps.
the distance is obtained by knowing the perimeter of the circle in question, this Canberra determined using the rule for circle circunfrence. As for the displacement it is the shortest distance between the starting pint of travel and ending. If for example the vehicle traveled around the whole circunfrence of a circle it will have a displacement of zero, as for it's distance it will be the length or circunfrence of the circle.
Sure. As one car goes around a circle and as it completes one full rotation, then distance covered by the car is the circumference of the circle. But the displacement is Zero. So distance but no displacement.
Displacement is the straight line distance between two points. If the two points are a half a lap apart on a circular path then the straight line distance is the diameter of the circle; 350 m. What that means is that displacement describes only the relationship between end position and starting position, so the car stops at a point on the opposite side of the circle, 350m from the start. Displacement is not necessarily distance traveled. If the car had gone completely around the circle and stopped where it started, the displacement would be zero, even though it has traveled nearly 1100 m.
No, displacement cannot be greater than distance. Displacement represents the straight-line distance between the initial and final positions of an object, while distance is the total length of the path traveled. Since displacement is the shortest distance between two points, it cannot be greater than the total distance traveled.
Total path is distance Where as the straight line is the displacement In case of a body going aroung a circle completing one full round, the distance is 2piR But the displacement is ZERO There by distance is a scalar and so it does not have direction But displacement is a vector. Because of vector addition we get displacement in this case as ZERO
Displacement is a vector quantity while distance is a scalar quantity. so in case of displacement, it depends on final position. For example:- If a man walks on a circle, then if he completes one round then his displacement will be zero because the man is at same position as start position. But, his distance travelled will not be zero; it is equal to circumference of the circle.
Yes distance will be equal or more than the magnitude of displacement. Distance cannot be less than the magnitude of displacement in any way. For example if a body goes around a circle completing one full round then distance covered will be the circumference ie 2pi r But displacement is zero. As the starting and stopping point are one and the same, the distance between initial and final is zero.
when the body moves circularly from a point 'A' to a then the displacement will be zero(displacement is the shortest diatance from the initial point to final point) and the distance will not be zero.
The magnitude of the displacement of an object that has traveled in a semicircle (a half circle) is not the DISTANCE that it traveled, but the shortest distance between it's starting point and it's ending point. This means that the diameter of the semicircle = the displacement, so 15.2*2=30.4 cm is the answer.
The distance and displacement are the same when the displacement is parallel to itself or straight. Displacement is a vector and distance is a real number or scalar. If an object is displaced around a circle the displacement is zero and the distance is 2pi r.