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If your initial velocity was 10 ms-1 right and your final velocity was 5 ms-1 left what is your change in velocity?
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∙ 14y ago
The change in velocity is 15 m/s left.
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∙ 14y ago
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What is the effect of changing the initial position on position time and velocity time graph?
Changing the initial position on a position vs time graph has no effect on the velocity vs time graph. Velocity is the derivative of position. This means velocity only depends on the rate of change (slope) of position. Changing the initial position of an object has no effect on the slope. Mathematically, this is equivalent to adding a constant to a function. Since the derivative of a constant is always 0, a change in initial position has no impact on the derivative. Here is an example. Say we have the position functions x(t)= 4+9t and y(t)= 27+9t. then the velocity function of x would be x'(t)=v(t)= 9 And the velocity function of y would be Y'(t)=v(t)= 9
A force of 315N is applied to a crate to displace it 35m across a floor at constant velocity The internal energy increases by 14percent of initial internal energy what was the initial internal energy?
1543.5 is the answer w=F*s = 315*35 =11025 this is the final or total internal energy now use the formula of percentage 14/100=initial internal energy/11025 (14/100)*11025=internal energy i cannot say with surety that this is right
What would happen to an objects's velocity if no work was being done on the object?
The velocity might still change, in the case of a force applied at a right angle to the movement. In this case, since the object's direction changes, its velocity changes.
How can you find initial velocity when the displacement is given but time is not?
Unfortunately, the question is so vague it can't be answered specifically. But I will use my intuition and say that you are a high-school student studying algebra-based physics and are now up to the chapter or unit on rectilinear motion. If so, read on. If not, well, then perhaps you could use the discussion page to add more info (and maybe rephrase the question). The general formula for straight-line motion is a quadratic equation. Displacement (or distance) is expressed as a function of time. In other words, dispacement is the dependent variable and time is the independent variable. But displacement is also dependent upon the values of initial displacement, initial velocity, and acceleration, which are all coefficients of the general displacement formula. Here is the formula: d = d0 + v0t + (1/2)at2, where d is the displacement, d0 is the initial displacement (in other words, the displacement at t = 0), v0 is the initial velocity (velocity at t = 0), and a is the acceleration. So, using the formula, you can solve for distance traveled (displacement) if you know the values of all those parameters to the right of the equal sign. But what if you don't know the value of t? Well, in that case, you had better know the values of all the other parameters, including the d to the left of the equal sign. If you know the initial distance, the total distance traveled, the initial velocity, and the acceleration, you can solve for t. Usually, we set up our frame of reference so that d0 = 0. Frequently, v0 = 0, also. (In other words, the object has no initial displacement and no initial velocity.) If you know the distance traveled, d, and the acceleration, a, then you can solve for t using the simplified formula d = (1/2)at2. Solving for t, you get t = SQRT(2d/a).Since you now know t and d, you can calculate the object's average velocity using the formula, va = d/t. Since the object started at rest (it had zero initial velocity), its final velocity, vf, is 2va. You might be able to use the equation of motion v2 = u2 + 2ad, where v is the final velocity, u is the initial velocity, a is the acceleration & d is the distance covered. Quite often the initial velocity is zero, so the equation simply becomes v2 = 2ad. So the final velocity v =SQRT(2ad).
When throwing a ball straight up when is the velocity zero?
The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
If a ball rolls off the edge of a table two meters above the floor and with an initial velocity of 20 meters per second what is the ball's acceleration and velocity just before it hits the ground?
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
If a batter hits a baseball upward into right field does its velocity change?
yes
What is the effect of changing the initial position on position time and velocity time graph?
Changing the initial position on a position vs time graph has no effect on the velocity vs time graph. Velocity is the derivative of position. This means velocity only depends on the rate of change (slope) of position. Changing the initial position of an object has no effect on the slope. Mathematically, this is equivalent to adding a constant to a function. Since the derivative of a constant is always 0, a change in initial position has no impact on the derivative. Here is an example. Say we have the position functions x(t)= 4+9t and y(t)= 27+9t. then the velocity function of x would be x'(t)=v(t)= 9 And the velocity function of y would be Y'(t)=v(t)= 9
A force of 315N is applied to a crate to displace it 35m across a floor at constant velocity The internal energy increases by 14percent of initial internal energy what was the initial internal energy?
1543.5 is the answer w=F*s = 315*35 =11025 this is the final or total internal energy now use the formula of percentage 14/100=initial internal energy/11025 (14/100)*11025=internal energy i cannot say with surety that this is right
Are rates of change always constant?
If I understand correctly your question, the answer is definitely no.Think about the typical physical representation of the concept of "rate of change": the velocity is the rate of change of position, right? And there's no difficulty in imagining a non-constant velocity, as when you accelerate or decelerate..
How can you find initial velocity when the displacement is given but time is not?
Unfortunately, the question is so vague it can't be answered specifically. But I will use my intuition and say that you are a high-school student studying algebra-based physics and are now up to the chapter or unit on rectilinear motion. If so, read on. If not, well, then perhaps you could use the discussion page to add more info (and maybe rephrase the question). The general formula for straight-line motion is a quadratic equation. Displacement (or distance) is expressed as a function of time. In other words, dispacement is the dependent variable and time is the independent variable. But displacement is also dependent upon the values of initial displacement, initial velocity, and acceleration, which are all coefficients of the general displacement formula. Here is the formula: d = d0 + v0t + (1/2)at2, where d is the displacement, d0 is the initial displacement (in other words, the displacement at t = 0), v0 is the initial velocity (velocity at t = 0), and a is the acceleration. So, using the formula, you can solve for distance traveled (displacement) if you know the values of all those parameters to the right of the equal sign. But what if you don't know the value of t? Well, in that case, you had better know the values of all the other parameters, including the d to the left of the equal sign. If you know the initial distance, the total distance traveled, the initial velocity, and the acceleration, you can solve for t. Usually, we set up our frame of reference so that d0 = 0. Frequently, v0 = 0, also. (In other words, the object has no initial displacement and no initial velocity.) If you know the distance traveled, d, and the acceleration, a, then you can solve for t using the simplified formula d = (1/2)at2. Solving for t, you get t = SQRT(2d/a).Since you now know t and d, you can calculate the object's average velocity using the formula, va = d/t. Since the object started at rest (it had zero initial velocity), its final velocity, vf, is 2va. You might be able to use the equation of motion v2 = u2 + 2ad, where v is the final velocity, u is the initial velocity, a is the acceleration & d is the distance covered. Quite often the initial velocity is zero, so the equation simply becomes v2 = 2ad. So the final velocity v =SQRT(2ad).
What would happen to an object's velocity if no work was being done on the object?
The velocity might still change, in the case of a force applied at a right angle to the movement. In this case, since the object's direction changes, its velocity changes.
What would happen to an objects's velocity if no work was being done on the object?
The velocity might still change, in the case of a force applied at a right angle to the movement. In this case, since the object's direction changes, its velocity changes.
When throwing a ball straight up when is the velocity zero?
The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
How do you get the velocity of a grape?
it depends on the situation the grape is in! Velocity is the change in distance / change in time... for example: if a car moves 3 meters in 1 second. the car has a velocity of 3 m/s... or 6 meters in 2 seconds.. its velocity is still 3m/s velocity is a vector quantity however so you must be careful while solving velocity related problems... basically this means that velocity is also measured by which direction the object is moving.... if the car from the previous example is moving to the right, its velocity would be +3m/s.... if it were moving to the left it would be -3m/s. (moving left or right is all relative to the starting position of the car).
Why do electrons in a uniform magnetic field travel in a circular path?
It's because of how magnetic force is. The magnetic force is always perpendicular to both the magnetic field and the velocity of the electron, or any charged particle. If you draw x's on a piece of paper, representing the direction of the magnetic field into the paper, then draw a short vertical line up, representing the electron velocity, the magnetic force will be horizotal to the right. This causes the velocity to change direction a little toward the right. But now the force must change direction a little, etc., etc, until you get a circular path. BTW, you only get a circular path if the initial velocity is in the plane of the paper, perpendicular to the field. If the electron comes in at an angle from outside the paper the path will be a "screw" shape, circular and forward at the same time.
What occurs any time an object speeds up or slows down or changes direction?
Acceleration. Acceleration is change in velocity. Velocity is its speed and direction. So when one of these things changes, it is undergoing acceleration. Acceleration can be the object speeding up, slowing down, turning right, turning left, etc. Deceleration is lowering the rate of change. You are experiencing no change if you are moving in a straight line at a constant speed.
