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Yes, they are. anti-stockes lines are less intense than stockes at room temperature because the no. of molecules in the lowest excited vibrational level is less than that in the next higher excited vib. level... and since the intensity of the lines depends on the population of molecules.... it have weaker lines.... but at thermal equilibriume.... the no. of molecules in the next higher excited vib. level is higher than that in the lowest one....so the intensity of the anti-stockes is higher than the stockes........!!!

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16y ago

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