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In an isolated system two cars each with a mass of 1500 kg collide Car 2 is initially at rest while Car 1 was moving at 20 m s What is their final speed?
To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.
In an isolated system two cars each with a mass of 1000 kg collide Car 1 is initially at rest while Car 2 was moving at 10 ms They move off together What is their speed?
Their speed after the collision would be 5 m/s. This can be calculated using the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision in an isolated system. Since Car 1 was initially at rest (0 m/s) and Car 2 was moving at 10 m/s, their total momentum before the collision would be m * v = 1000 kg * 10 m/s = 10000 kg⋅m/s. After the collision, this total momentum would be divided between the two cars, resulting in a speed of 5 m/s for the combined system.
Is an isolated system two cars each with a mass of 2000 kg collide car 1 is initially at rest while car 2 was moving at 20 ms what is their combined momentum after the collision?
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
In an isolated system two cars each with a mass of 1000 kg collide car 1 is initially at rest while car 2was moving at10ms what is the magnitude of their combined momentum after the collision?
The total momentum before the collision is 10,000 kg m/s (1000 kg * 10 m/s) in the direction of Car 2's initial velocity. Since the system is isolated, momentum is conserved. After the collision, the total momentum is still 10,000 kg m/s, but now shared between the two cars.
In an isolated system two cars each with a mass of 2500 kg collide. Car 1 is initially at rest while Car 2 was moving at 20 ms. What is their speed after the collision?
10 m/s
In an isolated system two roller skaters each with a mass of 100 kg collide Skater 1 was initially at rest while Skater 2 was moving at 6 ms They move off together What is their speed?
They move with a speed of 3 ms^-1.
In an isolated system two roller skaters each with a mass of 100 kg collide skater 1 was initially at rest while skater 2 was moving at 6 ms. They move off together. What is their speed?
They move with a speed of 3 ms^-1.
In an isolated system two cars each with a mass of 1000 kg collide Car 1 is initially at rest while Car 2 was moving at 10 m s They move off together What is their speed?
5 m/s APPEX ;)
In an isolated system two cars each with a mass of 1000 kg collide Car 1 is initially at rest while Car 2 was moving at 10 ms What is the magnitude of their combined momentum at the collision?
10,000
In an isolated system two cars each with a mass of 1500 kg collide Car 2 is initially at rest while Car 1 was moving at 5 ms What is their final speed?
7,500 Kg-m/s
In an isolated system two cars each with a mass of 1000 kg collide Car 1 is initially at rest while Car 2 was moving at 10 ms What is the magnitude of their combined momentum after the collision?
10,000 kg-m/s
In an isolated system two cars each with a mass of 1000 kg collide. Car 1 is initially at rest while Car 2 was moving at 10 ms. What is the magnitude of their combined momentum after the collision?
10,000 kg-m/s
In an isolated system, two cars, each with a mass of 1,000 kg, collide Car 1 is initially at rest, while Car 2 was moving at 10 m/s What is the magnitude of their combined momentum after the collisi?
10,000 kg-m/s
In an isolated system two cars each with a mass of 1500 kg collide. Car 1 is initially at rest while Car 2 was moving at 5 ms. What is their combined momentum after the collision?
Law of Conservation of Momentum: The total momentum after the collision is equal to the total momentum before the collission.
In an isolated system two cars each with a mass of 2000 kg collide Car 1 is initially at rest while Car 2 was moving at 20 ms What is their combined momentum after the collision?
Their combined momentum was 40,000 kg-m/s: 2000kg X 20 m/s= 40000 kg-m/s.
In an isolated system two cars each with a mass of 1500 kg collide Car 2 is initially at rest while Car 1 was moving at 20 m s What is their final speed?
To find the final speed after the collision, you would need to consider conservation of momentum in an isolated system. If the collision is perfectly elastic, you can use the equation: m1v1i + m2v2i = m1v1f + m2v2f. With Car 2 initially at rest (v2i=0) and Car 1 moving at 20 m/s (v1i=20 m/s), you can solve for the final velocity of both cars.
Why does the LHC have two beams?
The "C" stands for "Collider" For something to collide there has to be a second something moving in a different direction to collide with. The contents of the two beams moving in opposite directions collide.
