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This question can't be answered as asked. A string vibrating at its fundamental frequency has nothing to do with the speed of the produced sound through air, or any other medium. Different mediums transmit sound at different speeds.

The formula for wavelength is L = S/F, were L is the wavelength, S is the speed through the medium and F is the frequency. Therefore, the wavelength depends on the speed of sound through the medium and directly proportional to the speed and inversely proportional to the frequency.

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What is the relationship between the wavelength of the fundamental frequency of a tube with open ends and its length, as described by the statement that the wavelength is equal to 4 times the length of the tube?

The relationship between the wavelength of the fundamental frequency of a tube with open ends and its length is described by the statement that the wavelength is equal to 4 times the length of the tube. This means that the wavelength of the sound wave produced in the tube is four times the length of the tube.


A tight guitar string has a frequency of 540 Hz as its third harmonic what will be its fundamental frequency if it is fingered at a length of only 60 percent of its original length?

normal fundamental- 180 Hz (open- open) = 540 Hz at 3rd- f at 3rd= 3f' 540 =180 it's wavelength= v/f= 343/180= 1.9 L= 3/2 (wavelength)= 2.85 60% of this = 1.71= new wavelength v= f x wavelength 343/ 1.71= 200 Hz


How does the frequency of a wave relate to its wave length?

The frequency of a wave is inversely proportional to its wavelength. This means that as the frequency of a wave increases, its wavelength decreases, and vice versa. This relationship is based on the fundamental properties of wave motion.


How does changing length affect sound?

Changing the length of a vibrating object, such as a string or air column, affects the frequency of the sound produced. Shortening the length typically results in a higher frequency or pitch, while lengthening it results in a lower frequency or pitch. This is due to the relationship between the wavelength of the sound wave and the size of the vibrating object.


How long is a rope if its standing wave fundamental frequency has a wavelength of 10 meters?

The length of the rope would be half the wavelength of the standing wave, so in this case, the rope would be 5 meters long. This is because the fundamental frequency of the standing wave has one full wavelength, which corresponds to half the length of the rope.

Related Questions

What is the relationship between the wavelength of the fundamental frequency of a tube with open ends and its length, as described by the statement that the wavelength is equal to 4 times the length of the tube?

The relationship between the wavelength of the fundamental frequency of a tube with open ends and its length is described by the statement that the wavelength is equal to 4 times the length of the tube. This means that the wavelength of the sound wave produced in the tube is four times the length of the tube.


A tight guitar string has a frequency of 540 Hz as its third harmonic what will be its fundamental frequency if it is fingered at a length of only 60 percent of its original length?

normal fundamental- 180 Hz (open- open) = 540 Hz at 3rd- f at 3rd= 3f' 540 =180 it's wavelength= v/f= 343/180= 1.9 L= 3/2 (wavelength)= 2.85 60% of this = 1.71= new wavelength v= f x wavelength 343/ 1.71= 200 Hz


How does the frequency of a wave relate to its wave length?

The frequency of a wave is inversely proportional to its wavelength. This means that as the frequency of a wave increases, its wavelength decreases, and vice versa. This relationship is based on the fundamental properties of wave motion.


How does changing length affect sound?

Changing the length of a vibrating object, such as a string or air column, affects the frequency of the sound produced. Shortening the length typically results in a higher frequency or pitch, while lengthening it results in a lower frequency or pitch. This is due to the relationship between the wavelength of the sound wave and the size of the vibrating object.


How long is a rope if its standing wave fundamental frequency has a wavelength of 10 meters?

The length of the rope would be half the wavelength of the standing wave, so in this case, the rope would be 5 meters long. This is because the fundamental frequency of the standing wave has one full wavelength, which corresponds to half the length of the rope.


How do you ensure if wire is vibrating in the fundamental mode in a sonometer?

To ensure that a wire is vibrating in the fundamental mode in a sonometer, adjust the tension until the wire vibrates with a single loop in the center. This setup will produce the fundamental frequency of vibration. Additionally, you can make small adjustments to the tension and length of the wire to further ensure the wire is vibrating in the fundamental mode.


The frequencies at which standing waves are made are called?

wavelength. The larger the frequency, the smaller the wavelength.


How are the overtones related to the fundamental frequency of a vibrating string?

The fundamental = 1st harmonic is not an overtone!Fundamental frequency = 1st harmonic.2nd harmonic = 1st overtone.3rd harmonic = 2nd overtone.4th harmonic = 3rd overtone.5th harmonic = 4th overtone.6th harmonic = 5th overtone.Look at the link: "Calculations of Harmonics from FundamentalFrequency".


What is the wave length of a frequency of X?

The wavelength of a wave with frequency X can be calculated using the formula: wavelength = speed of light / frequency.


Who to get frequency from length and speed?

Frequency = (speed of the wave) divided by (wavelength)


What happens to frequency if string length doubles?

If the string length doubles, the frequency of the vibrating string decreases by half. This is because frequency is inversely proportional to the length of the string.


Law of vibrating strings?

The law of vibrating strings is the vibrational mode of a string that is stretched. The wavelength is twice the length of the string.