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What is the energy of a photon that emits a light of freqeuncy7.21x1014hz?
The energy of a photon is given by the equation E = hf, where E is the energy, h is Planck's constant (6.63x10^-34 J-s), and f is the frequency of the light. Plugging in the values, the energy of the photon is approximately 4.78x10^-19 joules.
What is the energy of a photon that emits a light of frequency 4.47X 1014 Hz?
2.96 x 10^-19 J
What is the energy of a photon that emits a light of frequency 4.471014?
The energy of a photon is given by E=hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of light. Thus, the energy of the photon emitting light of frequency 4.471014 Hz is approximately 2.97 x 10^-33 Joules.
What is the energy of a photon that emits a light of frequency 6.421014 Hz?
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the values, the energy of the photon emitting light of frequency 6.421014 Hz would be approximately 4.25 x 10^-33 Joules.
What is the energy of a photon that emits a light of frequency energy 7.211014 Hz?
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the given frequency of 7.211014 Hz into the equation, we find that the energy of the photon is approximately 4.79 x 10^-33 J.
What is the energy of a photon that emits a light of freqeuncy7.21x1014hz?
The energy of a photon is given by the equation E = hf, where E is the energy, h is Planck's constant (6.63x10^-34 J-s), and f is the frequency of the light. Plugging in the values, the energy of the photon is approximately 4.78x10^-19 joules.
An atom that undergoes excitation and de-excitation emits?
An atom that undergoes excitation and de-excitation emits photons of light. When an electron in an atom absorbs energy and moves to a higher energy level (excitation), it eventually returns to its original state (de-excitation) and emits a photon of light corresponding to the energy difference between the two levels.
What is the energy of a photon the emits a light of frequency 6.42 1014 Hz?
4.25 10-19 j
Whenever an excited hydrogen atom falls back from an excited state to its ground state it?
emits a photon with a specific energy corresponding to the difference in energy levels between the excited state and the ground state. This emitted photon can be in the form of visible light, ultraviolet light, or infrared light depending on the specific energy transition. This process is known as emission spectroscopy and is used to identify elements based on the unique energy levels of their electron configurations.
What is the energy of a photon that emits a light of frequency 4.47X 1014 Hz?
2.96 x 10^-19 J
When a electron returns to its stable or ground state is emits?
When an electron returns to its stable or ground state, it emits a photon of light. This process is known as emission and is responsible for various forms of light emission including fluorescence, phosphorescence, and luminescence. The energy of the emitted photon is equivalent to the energy difference between the higher energy state and the lower stable state of the electron.
What is the energy of a photon that emits a light of frequency 4.471014?
The energy of a photon is given by E=hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of light. Thus, the energy of the photon emitting light of frequency 4.471014 Hz is approximately 2.97 x 10^-33 Joules.
What is the energy of a photon that emits a light of frequency 4.47 x 1014 Hz?
2.96 x 10-19 J
What is the energy of a photon that emits a light of frequency 6.421014 Hz?
The energy of a photon is given by E = hf, where h is the Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the values, the energy of the photon emitting light of frequency 6.421014 Hz would be approximately 4.25 x 10^-33 Joules.
What is the energy of a photon that emits a light of frequency energy 7.211014 Hz?
The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the given frequency of 7.211014 Hz into the equation, we find that the energy of the photon is approximately 4.79 x 10^-33 J.
What change occurs with the atom when it is emitting light?
When an atom emits light, an electron in the atom transitions from a higher energy state to a lower energy state. This transition releases energy in the form of a photon of light. The atom remains the same element before and after emitting light.
What happens to excess energy when the electron jumps from a higher energy orbit to a lower energy orbit in the hydrogen atom?
The electron emits a photon of light which we can see in a spectrograph as color. Four colors are normally seen in a hydrogen atom subjected to energy.
