No, for example (-yi +xj)/(x^2 + y^2) is irrotational but not conservative on the domain {(x,y}|x^2 + y^2 > 0}.
A vector field is considered conservative when its curl is zero.
Yes, the magnetic field is a vector quantity because it has both magnitude and direction.
No, the velocity vector of a charged particle is not affected by the electric field if it is perpendicular to the field. The electric force acting on the particle is zero in this case because the force is given by the product of charge and the component of electric field parallel to the velocity vector.
Yes, the gravitational field is a vector quantity. It has both magnitude (strength) and direction, which are important in determining the effect of gravity on objects within the field.
Gravitational field is a vector quantity, as it has both magnitude (strength) and direction. It represents the force experienced by a mass placed in the field due to the presence of another mass.
A vector field is considered conservative when its curl is zero.
Irrotational,rotational,solenoidal vecter field
Irrotational fields are conservative, simply connected (path independent), and have no curl (del cross the field) = 0Rotational fields are orthogonal MTM=I, symmetrical, representable in any finite dimension through orthogonal matrix multiplication
No, the curl of a vector field is a vector field itself and is not required to be perpendicular to every vector field f. The curl is related to the local rotation of the vector field, not its orthogonality to other vector fields.
Yes. For any vector field, force included, to be conservative, it must be irrotational, meaning that its curl must be zero everywhere. Fortunately (for me at least, since it makes this answer a whole heck of a lot easier to explain), the magnetic force field vector is already commonly expressed as a curl via Maxwell's equations:∇ X B = μ0J + μ0ε0∂E/∂t,where B is the magnetic field, μ0 is the permeability of free space, ε0 is the permittivity of free space, J is the current density, E is the electric field, t is time, and ∇ X B is the curl of the magnetic field. Bolded quantities are vectors.Now, if you don't know a thing about vector calculus, hopefully you at least remembered what I wrote above. For a vector field to be conservative, its curl must be zero everywhere. As you can hopefully see from that above equation, the curl of the magnetic field, ∇ X B, is not zero everywhere. More specifically, if there is a current density, J, within the magnetic field, or if there is a time changing electric field, ∂E/∂t, within the magnetic field, the curl of the magnetic field is not zero, therefore the magnetic force field is nonconservative.If you get lucky enough to find a situation where there is no current density or time dependent electric field, which is in reality impossible due to electrons providing there own time dependent electric fields, then the magnetic force field would be conservative.
Vector.
Divergence and curl are two fundamental operators in vector calculus that describe different aspects of a vector field. The divergence of a vector field measures the rate at which "stuff" is expanding or contracting at a point, indicating sources or sinks in the field. Mathematically, it is represented as the dot product of the del operator with the vector field. Curl, on the other hand, measures the rotation or circulation of the field around a point, indicating how much the field "curls" or twists; it is represented as the cross product of the del operator with the vector field.
no
it is not a conservative feild....it is a non conservative feild
Yes, the magnetic field is a vector quantity because it has both magnitude and direction.
Scaler. The electric field is its vector counterpart.
Direction of the electric field vector is the direction of the force experienced by a charged particle in an external electric field.