There are two answers to your question, and they depend on whether we're talking about electrostatics or electrodynamics.
Electrostatics:No. In the absence of a varying magnetic field, the electric field intensity is equal to just the negative gradient of the electric potential; E = -∇Φ. So, if Φ is 0, its gradient, which is just the vector field made from the partial derivatives of Φ, has to be 0. The reverse, however, can happen. E can be 0, but Φ doesn't have to be; it can also be a non-zero constant. Electrodynamics:Yes. In the presence of a varying magnetic field, E = -∇Φ - ∂A/∂t, where A is the magnetic vector potential, and t is time. So, if Φ is 0 this time, E can still be equal to the possible non-zero term, -∂A/∂t.Highly unlikely, but possible none the less.
A positive test charge of 1.6 x 10-11 C is placed in an electric field The force acting on it is 3.2 x 10-4 N What is the magnitude of the electric field intensity at the point where the charge is placed
No. If two equipotential surfaces intersect, then there would be two values of electric potential at the point of intersection, which is not possible.
Because the potential energy consumed or released when a charge is moved from any point to any other point (in an unchanging electric field) is independent of the path. Therefore the potential at any point is represented by a single number (of volts, if you like). If it's a single-number function of position, it's a scalar that has no direction. The gradient of the potential function on the other hand is a vector, the electric field.
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Electric potential energy is electric energy that is stored in a battery. so all the energy it creates is stored within the battery. It doesn't get used until someone uses it.=Electric potential is the amount of electric potential energy per one coulomb of charge at one point in a circuit compared to the potential energy per one coulomb of charge at another point in circuit also called voltage.=
The potential gradient gives the electric field intensity E at point in electric field which is directed from high to low potential. An electron being a negative charge particle therefore will tend to move from low potential to high potential, hence will move up the electric field
The potential gradient gives the electric field intensity E at point in electric field which is directed from high to low potential. An electron being a negative charge particle therefore will tend to move from low potential to high potential, hence will move up the electric field
It is only for our convinience. Electric Potential can be taken by using any point.
The voltage between point p and the battery is not able to measured exactly. You can never measure the absolute electric potential at any point. its just not possible. That is why we talk about difference in potential.
A positive test charge of 1.6 x 10-11 C is placed in an electric field The force acting on it is 3.2 x 10-4 N What is the magnitude of the electric field intensity at the point where the charge is placed
No. If two equipotential surfaces intersect, then there would be two values of electric potential at the point of intersection, which is not possible.
Because the potential energy consumed or released when a charge is moved from any point to any other point (in an unchanging electric field) is independent of the path. Therefore the potential at any point is represented by a single number (of volts, if you like). If it's a single-number function of position, it's a scalar that has no direction. The gradient of the potential function on the other hand is a vector, the electric field.
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it is defind as the amount of work done to bring a unit positive charge from infinity to that point in the electric feild it is devoted by V .: electric potential = workdone/charge V=w/q si unit is v
Electric potential energy is electric energy that is stored in a battery. so all the energy it creates is stored within the battery. It doesn't get used until someone uses it.=Electric potential is the amount of electric potential energy per one coulomb of charge at one point in a circuit compared to the potential energy per one coulomb of charge at another point in circuit also called voltage.=
Under an electric field, magnitude and direction of electric intensity is different in every point.If the electric intensity can be defined through a closed line (direction of electric intensity will be along the tangent of any point of that line)this is called electric lines of force. Electric lines of forces passing through an closed electric surface perpendicularly, is called electric flux.
THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.ORWE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA