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What is magnitude of electric field intensity due to dipole of length 2a at the mid point of line joining two charges?
The magnitude of the electric field intensity due to a dipole of length 2a at the midpoint of the line joining the two charges is given by: ( E = \frac{k \cdot p}{a^{3}} ), where ( E ) is the electric field intensity, ( k ) is the Coulomb constant, ( p ) is the dipole moment, and ( a ) is the length of the dipole.
Derive an expression for intensity of electric field at a point?
The intensity of an electric field at a point can be derived from Coulomb's law, which states that the electric field between two charges is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them. Mathematically, the expression for electric field intensity (E) at a point is given by (E = \frac{k \cdot |q|}{r^2}), where (q) is the charge creating the field, (r) is the distance from the charge to the point, and (k) is the Coulomb's constant.
What unit of Electric Intensity is?
The unit of electric intensity is volts per meter (V/m). Electric intensity represents the electric field strength at a specific point in space and is measured in terms of volts per meter.
How does electric field intensity form?
The electric field intensity is formed by the presence of electric charges. It is a vector quantity that represents the force experienced by a positive test charge per unit charge at a given point in space. The magnitude and direction of the electric field intensity depend on the distribution of charges in the vicinity.
Calculate the field due to an electric dipole of length 10 cm and consisting of charges of - plus 100 μC at appoint 20cm from each charge?
The electric field due to an electric dipole at a point along its axis is given by the formula: E = (kp)/r^3, where k is the electric constant (8.99 x 10^9 Nm^2/C^2), p is the dipole moment, and r is the distance from the midpoint of the dipole to the point. The dipole moment (p) is calculated by multiplying the magnitude of the charges by the distance between them, so p = 100μC x 0.1m = 10μC.m. Plugging in these values with r = 0.2m, you can calculate the electric field.
What is magnitude of electric field intensity due to dipole of length 2a at the mid point of line joining two charges?
The magnitude of the electric field intensity due to a dipole of length 2a at the midpoint of the line joining the two charges is given by: ( E = \frac{k \cdot p}{a^{3}} ), where ( E ) is the electric field intensity, ( k ) is the Coulomb constant, ( p ) is the dipole moment, and ( a ) is the length of the dipole.
Derive an expression for intensity of electric field at a point?
The intensity of an electric field at a point can be derived from Coulomb's law, which states that the electric field between two charges is directly proportional to the magnitude of the charges and inversely proportional to the square of the distance between them. Mathematically, the expression for electric field intensity (E) at a point is given by (E = \frac{k \cdot |q|}{r^2}), where (q) is the charge creating the field, (r) is the distance from the charge to the point, and (k) is the Coulomb's constant.
What unit of Electric Intensity is?
The unit of electric intensity is volts per meter (V/m). Electric intensity represents the electric field strength at a specific point in space and is measured in terms of volts per meter.
How does electric field intensity form?
The electric field intensity is formed by the presence of electric charges. It is a vector quantity that represents the force experienced by a positive test charge per unit charge at a given point in space. The magnitude and direction of the electric field intensity depend on the distribution of charges in the vicinity.
Calculate the field due to an electric dipole of length 10 cm and consisting of charges of - plus 100 μC at appoint 20cm from each charge?
The electric field due to an electric dipole at a point along its axis is given by the formula: E = (kp)/r^3, where k is the electric constant (8.99 x 10^9 Nm^2/C^2), p is the dipole moment, and r is the distance from the midpoint of the dipole to the point. The dipole moment (p) is calculated by multiplying the magnitude of the charges by the distance between them, so p = 100μC x 0.1m = 10μC.m. Plugging in these values with r = 0.2m, you can calculate the electric field.
What is the amplitude of the electric field in a given region of space?
The amplitude of the electric field in a given region of space refers to the maximum strength or intensity of the electric field in that area. It represents the peak value of the electric field's magnitude at any point within that region.
How are the field lines related to the intensity of an electric field?
an electric charge seas up an electric field in it's surroundings.it exerts force upon any charges which arrives in this field region.the force will be stronger when the field intensity is higher
What distinguish electric field intensity from electric potential stating the unit of each?
Electric Field Intensity also simply referred to as the Electric Field is a vector quantity with the units (V/m) (Volts per meter) Symbol: E (Boldface to represent a vector)Electric Potential is a scalar quantity with units V (Volts). Also sometimes referred to as Voltage when dealing with the difference between two points. Symbol: V (non-bolded to represent a scalar)The relationship between the two is:The Electric Field Intensity E is equal to the negative of the gradient of V.
What is the formula for calculating the electric field intensity at a distance r from a point charge q, given by E kq/r2, where k is the Coulomb's constant and r is the distance from the point charge?
The formula for calculating the electric field intensity at a distance r from a point charge q is E kq/r2, where k is Coulomb's constant and r is the distance from the point charge.
Derive the expression for electric potential as line integral dueto charge distribution and due to adipole?
The electric potential due to a charge distribution can be obtained by integrating the electric field over the path from infinity to the point of interest. This is given by the line integral of the electric field, V = -∫ E ⋅ dl. For a dipole, the electric potential can be derived by considering the potential contributions from both the positive and negative charges of the dipole. The expression for the electric potential due to a dipole is given by V = k * p ⋅ r / r^3, where k is the Coulomb constant, p is the dipole moment, r is the position vector pointing from the charge to the observation point, and the dot product signifies the cosine of the angle between p and r.
What is the significance of the electric field amplitude in the context of electromagnetic waves?
The electric field amplitude in electromagnetic waves represents the strength of the electric field at a given point. It is important because it determines the intensity of the wave and how much energy it carries. Higher electric field amplitudes correspond to more powerful waves with greater energy.
Can two electric field lines be drawn at a point?
No, two electric field lines cannot originate from the same point because the electric field direction at that point would be ambiguous. Electric field lines always point in the direction of the electric field at a given point and represent the direction a positive test charge would move in that field.
