The magnitude of the electric field intensity due to a dipole of length 2a at the midpoint of the line joining the two charges is given by: ( E = \frac{k \cdot p}{a^{3}} ), where ( E ) is the electric field intensity, ( k ) is the Coulomb constant, ( p ) is the dipole moment, and ( a ) is the length of the dipole.
The system of two point charges plus q and -q constitutes an electric dipole.In the case of an electric dipole ,the resultant field is parallel to the line joining the two charges at 1.any point on the line joining the charges 2.any point on the perpendicular bisector of the line joining the two charges.
Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.
The electrostatic force between two charges is called a central force because it acts along the line joining the two charges, targeting the center of the system formed by the charges. This means that the force is radial in nature, pointing towards or away from the central point between the charges.
Electromagnets are temporary magnets that produce a magnetic field when an electric current flows through them. They are commonly used in devices such as electric motors, speakers, and MRI machines. By controlling the flow of electricity, electromagnets can be turned on or off, making them versatile and useful in various applications.
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The system of two point charges plus q and -q constitutes an electric dipole.In the case of an electric dipole ,the resultant field is parallel to the line joining the two charges at 1.any point on the line joining the charges 2.any point on the perpendicular bisector of the line joining the two charges.
Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.
Coulomb's Law states that the magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each charge and inversely proportional to the square of the distance between the charges. A link is provided to the Wikipedia article.
Yes, it is possible to have zero electric field values at certain points between a negative and positive charge, depending on the distances and magnitudes of the charges. If the magnitudes of the charges are equal and the distances are adjusted accordingly, the electric fields may cancel each other out at specific points along the line joining the charges.
no, the charge would have to be of equal sign to achieve this.
The joining together of two or more conductors in an electric circuit.
developed in the 1780s by French physicist Charles Augustin de Coulomb The magnitude of the electrostatic force between two point electric charges is directly proportional to the product of the magnitudes of each charge and inversely proportional to the square of the distance between the charges. F = k q1q2 \ d2 As F is electric force k is coulomb's constant = 9*10^9 Nm^2\C^2 q1 and q2 are the charges measured in coulombs d is the distance between them measured in meters
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The electrostatic force between two charges is called a central force because it acts along the line joining the two charges, targeting the center of the system formed by the charges. This means that the force is radial in nature, pointing towards or away from the central point between the charges.
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The magnitude of the slope is the radial speed: that is, the speed towards or away from the starting point. This is not the speed of the object because it takes no account of the component of motion in a direction perpendicular to the line joining the object to the starting point.
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