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The system of two point charges plus q and -q constitutes an electric dipole.In the case of an electric dipole ,the resultant field is parallel to the line joining the two charges at

1.any point on the line joining the charges

2.any point on the perpendicular bisector of the line joining the two charges.

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Q and -q are two charges d distances apartFind locus of a point at which electric fields are parallel to the line joining the charges?

Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.


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The magnitude of the electric field intensity due to a dipole of length 2a at the midpoint of the line joining the two charges is given by: ( E = \frac{k \cdot p}{a^{3}} ), where ( E ) is the electric field intensity, ( k ) is the Coulomb constant, ( p ) is the dipole moment, and ( a ) is the length of the dipole.


Why electrostatic force also called central force?

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What is a parralel circuit?

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Related Questions

Q and -q are two charges d distances apartFind locus of a point at which electric fields are parallel to the line joining the charges?

Seems to me it has to be the line that passes through the mid-point of the line joining the charges, and perpendicular to it. It would be a line with slope = -1 / (slope of line joining the charges) and passing through the point that's (d/2) distant from both charges.


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