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Using the expression(see reference):

W = Fd cos(θ)

where:

F is the Force = 80 N

d is the Displacement = 10 m

θ is the Angle = 0 rad (As the push is horizontal)

we calculate the value for Work done(W):

W = 80*10*Cos[0]

∴ W = 800.0 Joule

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13y ago
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14y ago

Work = (force) x (distance) = (74) x (10) = 740 joules.

The mass of the mass that he's pushing is completely irrelevant.

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14y ago

W=Fxd=47Nx24m=1128Joules

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Q: Lee pushes a 21 kg mass 10 m across a floor with a horizontal force of 74 N Calculate the amount of work Lee does?
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