It goes horizontally. The string is the only force that is keeping the rock from going in a straight line (the rock will go in a straight line in the absence of a force because of its "inertia") Thus, if the force is removed when the rock's instantaneous velocity is horizontal, it will continue to travel horizontally thereafter (in the absence of gravity, another force)..
Yes. This is exactly the case when an object is thrown on the surface of the Earth. Consider an (American) football thrown in the air. This ball has the force of gravity accelerating it downward, but there is no force acting on it horizontally, thus there is no acceleration horizontally. As a result, since acceleration is the rate of change in velocity, the velocity in the vertical direction is changing, whereas the velocity in the horizontal direction is not.
They hit at almost exactly the same time. Just because the bullet from the gun is moving horizontally at high speed, this does not mean it escapes the pull of gravity. However, the direction of the fired bullet is "horizontal" (perpendicular to the vertical pull of gravity). This vector is very slightly tangential to the force of gravity, because the Earth is curved. So although the bullet path describes an arc, it is very, very slightly above the curvature of the Earth. The difference for this case would be practically immeasurable. However, for faster projectiles it would be proportionally larger.
UP is a relative term. It means "further from the ground", or more exactly, "further from Earth's centre". Buckminster Fuller suggested using 'out' and 'in' for 'up' and 'down'. Presumably, people in orbiting laboratories use 'up' and 'down' relative to their floor.
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force
Assuming the girl is exerting force exactly in the same direction she is travelling in:W=Fd or Work = Force x distance.Force: 200Ndistance: 10m200 x 10 = 2,000 so 2,000 J (joules) of work is done... ONLY if she is exerting force in exactly the same direction she is travelling in.
There is no such thing as exactly vertical because either it is vertical or it is not. You cannot have approximately vertical - it is not vertical, then. Vertical means at 90 degrees to the horizon (or horizontal).
Any line that is not running exactly straight up and down is not vertical. Any line that is not running exactly flat, left to right is not horizontal. Vertical and horizontal lines are always at 90 degrees to each other.
Depends on whether it is vertical or horizontal. If it is vertical, it is undefined. If it is horizontal, it is zero.
Yes, but any bit of force in any horizontal direction is always exactly cancelled by an equal-size bit of force in the opposite horizontal direction, so there's never a NET horizontal buoyant force. It's only apparent in the upward vertical direction.
Yes, but only if they are exactly vertical and exactly horizontal (90 degrees angular difference). For real-world examples, many vertical lines can be perpendicular to a single "horizontal" curved line at the points of intersection.
If the bubble is exactly centered the level is horizontal (or vertical if it is one of those)
No. Neglecting air resistance, the projectile follows a parabola. The horizontal distance is proportional to 'time', and the vertical distance is proportional to 'time squared'. This is exactly the description of a parabola.
Technically, a square is a rectangle with four lines of symmetry. A non-square rectangle has exactly two lines of symmetry: the vertical and the horizontal.
Press each of the vertical lines (|-) exactly once, and all four lines will go to horizontal (----). Now you can walk over the scorpion pit.
Everywhere. The zenith at a given point is the local vertical direction pointing away from the direction of the force of gravity at that location. In other words it is the point that is exactly straight up, no matter where you are on earth's surface.
dc
no, not exactly.