If the elevator is in free fall, you and the scale would be accelerating downward at the same rate. In this case, the scale would read zero, because you and the scale are essentially falling together with the same acceleration due to gravity.
well I would say using newtonian mechanics he would weight as F=M x g, 75x9.7 which equals 727.5 newtons.
On the way up:-Before the car started moving, it would read 490 newtons (110 pounds).-When the car started moving up, the scale would read more, until the car achieved its normal upward speed.-As long as the car maintained its steady normal speed, the scale would again read 490 newtons (110 pounds).-As the car approached its destination level and began to slow down, the scale would read less, until the car stopped.-When the car stopped, the scale reading would return to its normal 490 newtons (110 pounds).On the way down:-Before the car started moving, it would read 490 newtons (110 pounds).-When the car started moving down, the scale would read less, until the car achieved its normal downward speed.-As long as the car maintained its steady normal speed, the scale would again read 490 newtons (110 pounds).-As the car approached its destination level and began to slow down, the scale would read more, until the car stopped.-When the car stopped, the scale reading would return to its normal 490 newtons (110 pounds).================================All numbers are rounded. Acceleration of gravity is taken to be 9.8 meters (32.2 feet) per second2.
No, lifting one foot while standing on a scale does not change your weight. The scale measures the force exerted downward on it, regardless of how many feet are on it.
It will increase! if the elevator is moving with a constant velocity, then there will be no change in the reading as no acc. will be caused. but if the body moves downwards wit a uniform acc. of say suppose x m/s^2, then the weight if the body will decrease by F=m x a(of the lift) as the two vectors will be in the opp direction, i.e. downwards. the opposite applies when the when the body acc. in an upward direction, the vectors will be in an same direction and it will result in the scale reading turing up more! remmember, a sacle measures the upward force aka reaction force
We must use: (Force) = (Mass) x (Acceleration) Force = 400 N Acceleration = 9.8 m/(s^2) Mass = M 400 N = ( M ) x ( 9.8 m/(s^2)) After calculating, we find the mass of the man to be 40.82 kg.
If you had a 50kg weight on Earth, it would weigh ~zero on the space station. It would still have a mass of 50kg--meaning it would difficult to move, and hurt very bad if it wumped you on the head, but placed on a scale, it would show 0. Likewise, if you had that 50kg weight and a scale on an elevator here on Earth, the scale would read 50kg. Say at the top of a 100 floor building, the elevator's cable and safety devices broke and the elevator, you, the 50kg weight and the scale were all in free fall. For a very short time, the 50kg weight would weigh zero. You would weigh zero. The scale would weigh zero. Until the elevator hit the ground.
well I would say using newtonian mechanics he would weight as F=M x g, 75x9.7 which equals 727.5 newtons.
On the way up:-Before the car started moving, it would read 490 newtons (110 pounds).-When the car started moving up, the scale would read more, until the car achieved its normal upward speed.-As long as the car maintained its steady normal speed, the scale would again read 490 newtons (110 pounds).-As the car approached its destination level and began to slow down, the scale would read less, until the car stopped.-When the car stopped, the scale reading would return to its normal 490 newtons (110 pounds).On the way down:-Before the car started moving, it would read 490 newtons (110 pounds).-When the car started moving down, the scale would read less, until the car achieved its normal downward speed.-As long as the car maintained its steady normal speed, the scale would again read 490 newtons (110 pounds).-As the car approached its destination level and began to slow down, the scale would read more, until the car stopped.-When the car stopped, the scale reading would return to its normal 490 newtons (110 pounds).================================All numbers are rounded. Acceleration of gravity is taken to be 9.8 meters (32.2 feet) per second2.
No, lifting one foot while standing on a scale does not change your weight. The scale measures the force exerted downward on it, regardless of how many feet are on it.
Its not a questions of height or altitude. Its about things free falling. A space ship falling around the Earth (everything in the space ship is also falling at the same speed) the astronauts are falling too. If you put a scale on the floor and an astronaut stepped on it, there is no downward force so it looks like they are weightless. Picture yourself in an elevator at the top floor. You're standing on a scale. Gravity pulls you and the scale, but the elevator floor prevent you from falling. The scale will measure your weight. If the elevator suddenly fell, it, you and the scale would all be accelerating towards the basement at 9.8m/s/s. The scale would read ZERO, because there is no force acting on the scale.
The same as if you were not standing on your head.
It will increase! if the elevator is moving with a constant velocity, then there will be no change in the reading as no acc. will be caused. but if the body moves downwards wit a uniform acc. of say suppose x m/s^2, then the weight if the body will decrease by F=m x a(of the lift) as the two vectors will be in the opp direction, i.e. downwards. the opposite applies when the when the body acc. in an upward direction, the vectors will be in an same direction and it will result in the scale reading turing up more! remmember, a sacle measures the upward force aka reaction force
We must use: (Force) = (Mass) x (Acceleration) Force = 400 N Acceleration = 9.8 m/(s^2) Mass = M 400 N = ( M ) x ( 9.8 m/(s^2)) After calculating, we find the mass of the man to be 40.82 kg.
peanut butter
Most sources say either 6.9 or 7.1 so i suppose it would be 6.9-7.1
The reading on the scale would remain the same. Weight is a measurement of the gravitational force between you and the Earth, not the atmospheric pressure. Without the atmosphere, the force of gravity would still act on you, keeping your weight constant.
Add leg weight, roughly 45#.