I don't give a damn. Sorry couldn't resist.
The true value of g varies with latitude. I will take g=10 m/s2 because I'm lazy.
y= vxt -gt2
y=0, t=4.96s, g=10
0=4.96v-(10)(24.6016)
246.016 =4.96v
v= 49.6 m/s straight upwards.
You kicked the rock with an initial velocity of 3.4 m/s.
initial velocity would be ZERO before launch. To calculate the velocity you would need to hit that target at that distance you would need to know the mass of the rocket and the angle of launch or trajectory simplifying it
inelastic collision The formulas for the velocities after a one-dimensional collision are: where V1f is the final velocity of the first object after impact V2f is the final velocity of the second object after impact V1 is the initial velocity of the first object before impact V2 is the initial velocity of the second object before impact M1 is the mass of the first object M2 is the mass of the second object CR is the coefficient of restitution; if it is 1 we have an elastic collision; if it is 0 we have a perfectly inelastic collision
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
The speed of the vehicle before deceleration or braking.
You kicked the rock with an initial velocity of 3.4 m/s.
initial velocity would be ZERO before launch. To calculate the velocity you would need to hit that target at that distance you would need to know the mass of the rocket and the angle of launch or trajectory simplifying it
Reading this question very carefully and in great detail, and then subjecting it to several differentvarieties of microscopic, chemical, and molecular analysis, we're unable to find any informationpertaining to the initial velocity of Ball #2.We know that the two masses are equal, the initial velocities are in the same direction,the initial velocity of Ball #1 is 2 m/s, and that's it.We also note the peculiar nature of the question ... giving the velocity of one ball before collision,and then asking for both velocities beforecollision.That's like saying: My wife was in a fender-bender yesterday, with another car exactly likethe one she drives. She was going 30 mph before the collision. The other car was going inthe same direction. How fast were both cars going before the collision ?Weird !
To calculate the velocity after a perfectly elastic collision, you need to apply the principle of conservation of momentum and kinetic energy. First, find the initial momentum of the system before the collision by adding the momenta of the objects involved. Then, find the final momentum after the collision by equating it to the initial momentum. Next, solve for the final velocities of the objects by dividing the final momentum by their respective masses. Finally, make sure to check if the kinetic energy is conserved by comparing the initial and final kinetic energy values.
inelastic collision The formulas for the velocities after a one-dimensional collision are: where V1f is the final velocity of the first object after impact V2f is the final velocity of the second object after impact V1 is the initial velocity of the first object before impact V2 is the initial velocity of the second object before impact M1 is the mass of the first object M2 is the mass of the second object CR is the coefficient of restitution; if it is 1 we have an elastic collision; if it is 0 we have a perfectly inelastic collision
The horizontal velocity has no bearing on the time it takes for the ball to fall to the floor and, ignoring the effects of air resistance, will not change throughout the ball's fall, so you know Vx. The vertical velocity right before impact is easily calculated using the standard formula: d - d0 = V0t + [1/2]at2. For this problem, let's assume the floor represents zero height, so the initial height, d0, is 2. Further, substitute -g for a and assume an initial vertical velocity of zero, which changes our equation to 0 - 2 = 0t - [1/2]gt2. Now, solve for t. That gives you the time it takes for the ball to hit the floor. If you divide the distance traveled by that time, you know the average vertical velocity of the ball. Double that, and you have the final vertical velocity! (Do you know why?) Now do the vector addition of the vertical velocity and the horizontal velocity. Remember, the vertical velocity is negative!
Yes, if you turn a shape completely around to its original position it will look like its original position because it will be in its original position. For example if i take a trapezoid and turn it 180 degrees it does not look the same as it did before so it does not have rotational symmetry of 180 degrees.
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
Total momentum before = total momentum afterTotal kinetic energy before = total kinetic energy afterSum of x-components of velocity before = sum of x-components of velocity after.Sum of y-components of velocity before = sum of y-components of velocity after.Sum of z-components of velocity before = sum of z-components of velocity after.
The velocity is zero when t=v0/g. This comes from velocity of the ball is v=v0-gt, where v0 is the velocity which the ball is thrown with, the initial velocity. The balls v velocity is the initial velocity v0 - the gravity velocity gt. when the real velocity is zero v= v0-gt=0. solving this for t gives when the velocity is zero.
"Displacement = 0" means that at the end of the observation, the objectwas at the the same place as it was when the observation started.It may have traveled a million miles during the observation period, but iteventually returned to where it started.