I believe the answer is 35%. Since the formula for energy = useful work / total work input, you would then plug 35 j into the useful work and 100 under the total work input. You divide that and you get .35. Then, you multiply .35 by 100, and you get 35%.
The efficiency of the motor can be calculated by dividing the useful energy output by the total energy input and multiplying by 100. In this case, the efficiency would be 70J (useful energy output) divided by 100J (total energy input) = 0.7 or 70%.
The efficiency of the system would be calculated as the ratio of output work to input work, multiplied by 100% to express it as a percentage. In this case, the efficiency would be 82% (123j output work / 150j input work) * 100%.
The efficiency of the pulley system is calculated by dividing the output work by the input work and multiplying by 100, so efficiency = (output work/input work) * 100. In this case, the output work is 170 J and the input work is 250 J, so the efficiency is (170/250) * 100 = 68%.
The efficiency of the system can be calculated using the formula: efficiency = (output work / input work) * 100%. In this case, the efficiency would be (123 J / 150 J) * 100% = 82%.
The formula to find the work output of efficiency is: Work output = Efficiency x Input work. Efficiency is a ratio of output work to input work, so multiplying this ratio by the input work gives the work output.
The mechanical efficiency of this machine is 30 percent.
The efficiency of the motor can be calculated by dividing the useful energy output by the total energy input and multiplying by 100. In this case, the efficiency would be 70J (useful energy output) divided by 100J (total energy input) = 0.7 or 70%.
The efficiency of the system would be calculated as the ratio of output work to input work, multiplied by 100% to express it as a percentage. In this case, the efficiency would be 82% (123j output work / 150j input work) * 100%.
The efficiency of the pulley system is calculated by dividing the output work by the input work and multiplying by 100, so efficiency = (output work/input work) * 100. In this case, the output work is 170 J and the input work is 250 J, so the efficiency is (170/250) * 100 = 68%.
The idea is to divide the useful work by the input energy.
The efficiency of the system can be calculated using the formula: efficiency = (output work / input work) * 100%. In this case, the efficiency would be (123 J / 150 J) * 100% = 82%.
50
80%
The formula to find the work output of efficiency is: Work output = Efficiency x Input work. Efficiency is a ratio of output work to input work, so multiplying this ratio by the input work gives the work output.
Increasing the efficiency of a simple machine means that it requires less input work to produce the same output work. This results in less wasted energy and ultimately allows the machine to do more work with the same amount of input.
The machine efficiency is 35 percent (35/100).
If a machine has 100 percent efficiency, the output work = the input work. That's actually basically what the efficiency of a machine is - output work / input work * 100.