The machine efficiency is 35 percent (35/100).
94 percent (which is easily calculated, 3760/4000x100).
The efficiency of a machine tells you how much usefull energy it will put out compared to the amount of energy that's put in. The usefull output energy is usually less (never greater) then the input because of energy loss due to frictional heating. For example if 120 joules of energy or work is put into a lifting machine, you might only get out 110 joules of lifting work because 10 joules is lost to heat. The efficiency of the machine is then ; (110/120) x 100% = 91.7% . I think for most practical machines anything above 90% efficient is quite good. (The terms work & energy are used interchangebly here because work is a transfer of energy).
To calculate the mechanical energy provided by the motor, you need to divide the input energy by the efficiency of the motor. In this case, with 70% efficiency, you would divide 1960 joules by 0.70 to find that the mechanical energy provided would be approximately 2800 joules.
Efficiency is typically measured as the ratio of useful energy output to the total energy input, expressed as a percentage. In terms of joules, the efficiency can be calculated as the useful energy output in joules divided by the total energy input in joules, multiplied by 100. This calculation helps assess how effectively a system converts energy input into useful output.
The amount of heat energy produced from electrical energy depends on the efficiency of the system. If we assume 100% efficiency, then all 3000 joules of electrical energy would be converted into heat energy. Thus, 3000 joules of electrical energy would produce 3000 joules of heat energy.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
94 percent (which is easily calculated, 3760/4000x100).
The idea here is to divide the useful work by the input energy. (Note: Usually "power" would be used instead of "energy"; power is measured in joules/second.)
The efficiency of a machine tells you how much usefull energy it will put out compared to the amount of energy that's put in. The usefull output energy is usually less (never greater) then the input because of energy loss due to frictional heating. For example if 120 joules of energy or work is put into a lifting machine, you might only get out 110 joules of lifting work because 10 joules is lost to heat. The efficiency of the machine is then ; (110/120) x 100% = 91.7% . I think for most practical machines anything above 90% efficient is quite good. (The terms work & energy are used interchangebly here because work is a transfer of energy).
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To calculate the mechanical energy provided by the motor, you need to divide the input energy by the efficiency of the motor. In this case, with 70% efficiency, you would divide 1960 joules by 0.70 to find that the mechanical energy provided would be approximately 2800 joules.
Efficiency is typically measured as the ratio of useful energy output to the total energy input, expressed as a percentage. In terms of joules, the efficiency can be calculated as the useful energy output in joules divided by the total energy input in joules, multiplied by 100. This calculation helps assess how effectively a system converts energy input into useful output.
The amount of heat energy produced from electrical energy depends on the efficiency of the system. If we assume 100% efficiency, then all 3000 joules of electrical energy would be converted into heat energy. Thus, 3000 joules of electrical energy would produce 3000 joules of heat energy.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency is 80%. To find the efficiency, 400/500 = 80%.
The efficiency of the machine can be calculated as the ratio of useful work output to total work input, multiplied by 100 to express it as a percentage. In this case, the efficiency would be 80% (800/1000*100).
The comparison of joules between two energy sources affects their efficiency and effectiveness. Energy sources with higher joules are more efficient and effective in producing energy compared to those with lower joules. This is because higher joules mean more energy can be generated from the source, leading to better performance and productivity.