An impulse is simply a change of momentum, and momentum is defined as mass x velocity; so you just divide the momentum by the mass to get the velocity. Note about the units: newton x second is the same as kilogram x meter/second2.
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
Acceleration is the rate of change of velocity per time, so to get velocity, multiply (acceleration)*(time). This will give the change in velocity over the specific amount of time. You must add the initial velocity to get the final velocity, so we have the formula: Vf = Vo + a*t, where Vo is the initial velocity. This means that you can rearrange to get Vo = Vf - a*t
When given a constant acceleration, just multiply it by time, t, to detemine the final velocity. If the initial velocity was zero (as is the case when you drop something), then the average velocity is half the terminal velocity.
Impluse = m x v
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
(acceleration X time) + beginning velocity = final speed
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
Use the formula Acceleration = (final velosity - initial velocity)/ time.
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
the final velocity assuming that the mass is falling and that air resistance can be ignored but it is acceleration not mass that is important (can be gravity) final velocity is = ( (starting velocity)2 x 2 x acceleration x height )0.5
If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
The average acceleration is given by the expression a ∆v/∆t (15 m/s)/5s 3m/s2 where a is acceleration, v is velocity, and t is time. ∆ (final-initial) value.
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration
Acceleration is the rate of change of velocity per time, so to get velocity, multiply (acceleration)*(time). This will give the change in velocity over the specific amount of time. You must add the initial velocity to get the final velocity, so we have the formula: Vf = Vo + a*t, where Vo is the initial velocity. This means that you can rearrange to get Vo = Vf - a*t