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Try understanding this gem: :\langle\hat{T}\rangle = -\frac{\hbar^2}{2 m_e}\bigg\langle\psi \bigg\vert \sum_{i=1}^N \nabla^2_i \bigg\vert \psi \bigg\rangle If not, maybe you can use E(k)=1/2mv^2

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15y ago
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2mo ago

The kinetic energy of an electron can be calculated using the formula:

[ KE = \frac{1}{2}mv^2 ]

Since the kinetic energy is given as 13.65 eV, we can convert this to joules (1 eV = 1.6 x 10^-19 J) and use the mass of an electron (9.11 x 10^-31 kg) to solve for the velocity.

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Q: The kinetic energy of the hydrogen atom electron is 13.65 eV Find the velocity of the electron?
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What is more- potential energy or kinetic energy of an electron in hydrogen atom?

Both are equal.


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