The formula called Hooke's first law says that:
"F"(being the restoring force) = "-k"(the spring constant) times "x" (the displacement)
the negative is only for notations sake. and yes this means they are proportional, by means of the constant.
The elastic potential energy (EEp) of the spring with displacement x from its original length is given by: EEp = 1/2 kx2 (can be proved using integration) where k is the spring constant of the spring. So, if the displacement of the mass is doubled, the elastic EEp stored will increase by 22, that is by 4.
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
A spring scale is simply a spring fixed at one end with a hook to attach an object at the other. It works on the principle of Hookes Law, that states that the force needed to extend the spring is proportional to the distance that the spring extended from it's fixed position.
External force or you can say deformation force causes spring to stretch and restoring force is developed due to introduction of restoring strain in spring to restore in its original shape.
It may loose its elastic nature.
Hooke's law was designed to determine the restoring force of a spring, given its spring constant and the displacement of the spring from its equilibrium position. The law is written as follows: F = -kx; in which "F" is the restoring force, "k" is the spring constant, and "x" is the spring's displacement.
In case of HARMONIC OSCILLATOR the relation b/n FORCE AND DISPLACEMENT is LINEAR but in the case of ANHARMONIC OSCILLATOR relation b/n force and displacement is not linear.Hence this non-linearity arises the fact that the spring is not capable of exerting a restoring force that is proportional to the displacement.
The fact that the displacement of the spring (the amount it stretches) is proportional to the force.
The original length of the spring and the modulus of elasticity.
The spring constant is a measure of stiffness - the ability to resist displacement under a load. It is denoted by K where F = kx where f = load force and x = displacement
For a simple harmonic oscillator, the force is proportional to the displacement F=-kx, where F is the force, x is the displacement, and k is a positive proportionality constant commonly referred to as the spring constant
The elastic potential energy (EEp) of the spring with displacement x from its original length is given by: EEp = 1/2 kx2 (can be proved using integration) where k is the spring constant of the spring. So, if the displacement of the mass is doubled, the elastic EEp stored will increase by 22, that is by 4.
Moving coil galvanometer? If so, it is effectively an electric motor acting against a spring. the force from the motor is proportional to the current and the force from the spring is proportional to displacement. When they are equal, the needle (attached to the motor), stops. Moving iron meters rely on opposite magnetic poles repelling.
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
A spring scale is simply a spring fixed at one end with a hook to attach an object at the other. It works on the principle of Hookes Law, that states that the force needed to extend the spring is proportional to the distance that the spring extended from it's fixed position.
External force or you can say deformation force causes spring to stretch and restoring force is developed due to introduction of restoring strain in spring to restore in its original shape.
It may loose its elastic nature.