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The simple (and almost correct) answer is W = (Tend - Tstart) cp m = 50 X 2.51 X 50 = 6275 J In reality the constant cp isn't really a constant. cp(300 K) is closer to 2.2 JK-1g-1 than 2.51, which gives you an integral over the temperature shift, and a value that is slightly lower htan 6275 J.

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Q: The specific heat of methanol is 2.51 JK-gHow many joules are necessary to raise the temperature of 50g of methanol from 20 to 70 degrees celsius?
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