To increase the speed of rotation of the coil, you can increase the voltage applied to the coil or reduce the resistance in the circuit. Additionally, using a stronger magnetic field or reducing the friction in the system can also help increase the speed of rotation.
One way to increase the amount of electric current produced by a magnet is to increase the strength of the magnetic field. This can be done by using a stronger magnet or increasing the number of turns in the wire coil. Another way is to increase the speed at which the magnetic field changes, which can be achieved by moving the magnet or the wire coil faster.
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
You can increase the electrical energy in an electromagnet by increasing the current flowing through its coils. This can be done by either increasing the voltage of the power source or by using a coil with more turns to increase the magnetic field strength.
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
One way to increase the amount of electric current produced by a magnet is to increase the strength of the magnetic field. This can be done by using a stronger magnet or increasing the number of turns in the wire coil. Another way is to increase the speed at which the magnetic field changes, which can be achieved by moving the magnet or the wire coil faster.
.The magnitude of the voltage and current of both the armature and shunt field coil. To decrease the speed when the load is increasing then increase the shunt field current while decreasing the armature voltage or current. To increase the speed while the load is increasing then increase the armature current while decreasing the shunt field current. The decreasing and increasing of these currents and voltages can be done by connecting a variable resistor in series or parallel with each of the armature and/or shunt field coil.
DC shunt motor can be reversed by changing the polarity of either the armature coil or the field coil.
increase drive pulley size
ti can only be done by using hacking tools. there is no way to increase th speed of working in good game farmer.
To calculate the work done on the sled to increase its speed, you need to know the initial and final kinetic energy. The work done is equal to the change in kinetic energy, which is given by the formula: Work = (1/2) * m * (vf^2 - vi^2) Substitute the mass of the sled, initial speed, and final speed to find the work done.
You can increase the electrical energy in an electromagnet by increasing the current flowing through its coils. This can be done by either increasing the voltage of the power source or by using a coil with more turns to increase the magnetic field strength.
There are two alternate methods depending on whether the motor is single phase or three phase. On a single phase motor, reverse either the start winding coil lead or the run winding coil lead but not both. This action will reverse the motor's rotation. On a three phase motor, interchanging any two of the three coil leads will reverse the motor's rotation.
The work done is equal to the change in kinetic energy, which can be calculated using the formula: W = ΔKE = 1/2 m (v_f^2 - v_i^2). Plugging in the values, the work done to increase the speed of the scooter from 10 m/s to 20 m/s is 6000 J.
The work done to increase the speed of the scooter can be calculated as the change in kinetic energy. The initial kinetic energy is given by (1/2)mv^2. The final kinetic energy is (1/2)m(20)^2. The work done is the difference between the final and initial kinetic energies.
3000j
Work done = increase in kinetic energy ie 1/2 * 10 * (3+2)(3-2) [recall a2 - b2 = (a+b)(a-b)] Hence work done = 25 joule.