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What is the magnitude of the net electric force on the charge Q due to the other three charges?
That depends on where the charges are, and the magnitude of the charges. In general, you must calculate the vector for the force due to each individual charge, then add all the vectors together.
What is charge on charged particle of mass 2 mg which remains freely in air in electric field of 4 NC directed upwards. determine its nature?
The charge on the particle can be calculated using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength. Given that the force is the weight of the particle, we can calculate the charge as 8 µC. Since the charge is positive and the electric field is directed upwards, the nature of the charged particle is positive.
How can one determine the strength of an electric field?
The strength of an electric field can be determined by measuring the force experienced by a test charge placed in the field. The greater the force experienced by the test charge, the stronger the electric field. The formula to calculate the electric field strength is E F/q, where E is the electric field strength, F is the force experienced by the test charge, and q is the magnitude of the test charge.
How do you find the magnitude of the force between two protons?
Experiments have shown that the electric force between two objects is proportional to the inverse square of the distance between the two objects. The electric force between two electrons is the same as the electric force between two protons when they are placed as the same distance. This implies that the electric force does not depend on the mass of the particle. Instead, it depends on a new quantity: the electric charge. The unit of electric charge q is the Coulomb (C). The electric charge can be negative, zero, or positive. The electric charge of electrons, protons and neutrons are -1.6 x 10-19, 1.6 x 10-19, and 0. Detailed measurements have shown that the magnitude of the charge of the proton is exactly equal to the magnitude of the charge of the electron. Since atoms are neutral, the number of electrons must be equal to the number of protons. The precise magnitude of the electric force that a charged particle exerts on another is given by Coulomb's law.
A charge of plus Q attracts a charge of -Q 1 cm away with a force of F Another charge of plus Q is placed next to the first one The force on the charge of -Q is now?
If these are point charges each will apply a force F, so I guess the answer is 2F. If they are charges of finite physical size then the force from each won't be in line, so the result will be less.
What is the magnitude of the net electric force on the charge Q due to the other three charges?
That depends on where the charges are, and the magnitude of the charges. In general, you must calculate the vector for the force due to each individual charge, then add all the vectors together.
What is charge on charged particle of mass 2 mg which remains freely in air in electric field of 4 NC directed upwards. determine its nature?
The charge on the particle can be calculated using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength. Given that the force is the weight of the particle, we can calculate the charge as 8 µC. Since the charge is positive and the electric field is directed upwards, the nature of the charged particle is positive.
How can one determine the strength of an electric field?
The strength of an electric field can be determined by measuring the force experienced by a test charge placed in the field. The greater the force experienced by the test charge, the stronger the electric field. The formula to calculate the electric field strength is E F/q, where E is the electric field strength, F is the force experienced by the test charge, and q is the magnitude of the test charge.
The weight of a 1.2 kg object of charge Q is just balanced by another object of equal but opposite charge fixed to a support 102 cm above it What is the magnitude of the charge Q in microC?
Since weight is balanced by charge, set weight (mg) equal to Coulomb force (F) mg = k [(Q^2)/(r^2)]
How do you find the magnitude of the force between two protons?
Experiments have shown that the electric force between two objects is proportional to the inverse square of the distance between the two objects. The electric force between two electrons is the same as the electric force between two protons when they are placed as the same distance. This implies that the electric force does not depend on the mass of the particle. Instead, it depends on a new quantity: the electric charge. The unit of electric charge q is the Coulomb (C). The electric charge can be negative, zero, or positive. The electric charge of electrons, protons and neutrons are -1.6 x 10-19, 1.6 x 10-19, and 0. Detailed measurements have shown that the magnitude of the charge of the proton is exactly equal to the magnitude of the charge of the electron. Since atoms are neutral, the number of electrons must be equal to the number of protons. The precise magnitude of the electric force that a charged particle exerts on another is given by Coulomb's law.
A charge of plus Q attracts a charge of -Q 1 cm away with a force of F Another charge of plus Q is placed next to the first one The force on the charge of -Q is now?
If these are point charges each will apply a force F, so I guess the answer is 2F. If they are charges of finite physical size then the force from each won't be in line, so the result will be less.
Why a stationary charge do not feel any force in magnetic field?
we know that force on a charge in magnetic field F=qvbsinx q-charge v-velocity b-strenth 0f magnetic field x-angle between the motion of chage and the magnetic field as the charge is stationary so v=0 so,F=0 so charge donot fill any force on it.
What is the magnitude of the force acting on the electron due to its interaction with Earth and acirc and 128 and 153s magnetic field?
The force acting on the electron due to its interaction with Earth's magnetic field can be calculated using the equation F = qvB, where q is the charge of the electron, v is its velocity, and B is the magnetic field strength. Without specific values for the velocity and charge, we cannot calculate the magnitude of the force.
A charge experiences a force of 3.0x10-3 N in an electric field of 2.0 nc what is the magnitude of the charge?
The formula to calculate the force on a charge in an electric field is: ( F = qE ), where ( F ) is the force, ( q ) is the charge, and ( E ) is the electric field strength. Given ( F = 3.0 \times 10^{-3} , \text{N} ) and ( E = 2.0 , \text{N/C} ), we can rearrange the formula to solve for the charge, yielding ( q = \frac{F}{E} = \frac{3.0 \times 10^{-3}}{2.0} = 1.5 \times 10^{-3} , \text{C} ). Thus, the magnitude of the charge is ( 1.5 \times 10^{-3} , \text{C} ).
When the electric charge of to objects decreased what happeneds to the force?
Assuming that the only force on the two objects is an electric force. Felectric = k Q q / r2 This is Coulomb's law. K = electrostatic constant, Q and q are the magnitudes of the point charges, and r is the distance between the point charges. As you can see, if you decrease the magnitude of the charge, the electric force decreases. In other words, the objects are less attracted to one another. aside: gravity happens to be modeled the same way.
How you find answers of aipmt2008?
a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be a particle of mass m charge q & the K.E T enters a transverse uniform magnetic field of induction B after 3 sec the K.E of particle will be
How do you find acceleration due to magnetic field?
To find acceleration due to a magnetic field acting on a charged particle, you can use the equation ( F = qvB ), where ( F ) is the magnetic force, ( q ) is the charge of the particle, ( v ) is the velocity of the particle, and ( B ) is the magnetic field strength. Once you have calculated the magnetic force, you can use Newton's second law (( F = ma )) to find the acceleration (( a )) of the particle.
