The moment of inertia of a disk about its edge is equal to half of the mass of the disk multiplied by the square of its radius.
The formula for calculating the moment of inertia of a disk is I (1/2) m r2, where I is the moment of inertia, m is the mass of the disk, and r is the radius of the disk.
The mass moment of inertia of a disk is given by the equation I = (m * r^2) / 2, where m is the mass of the disk and r is the radius. This equation represents the resistance of the disk to rotational motion around its center.
The moment of inertia for a uniform disk is given by the formula I (1/2) m r2, where m is the mass of the disk and r is the radius of the disk.
The solid disk has a greater moment of inertia than the solid sphere because the mass of the disk is distributed farther from the axis of rotation, resulting in a larger rotational inertia. This difference can be explained by the parallel axis theorem, which states that the moment of inertia of an object can be calculated by adding the moment of inertia of the object's center of mass and the product of the mass and the square of the distance between the center of mass and the axis of rotation.
The moment of inertia of a hollow disk is given by (1/2) * m * (r_outer^2 + r_inner^2), where m is the mass of the disk, r_outer is the outer radius, and r_inner is the inner radius. This formula accounts for the distribution of mass around the central axis of the disk.
The formula for calculating the moment of inertia of a disk is I (1/2) m r2, where I is the moment of inertia, m is the mass of the disk, and r is the radius of the disk.
The mass moment of inertia of a disk is given by the equation I = (m * r^2) / 2, where m is the mass of the disk and r is the radius. This equation represents the resistance of the disk to rotational motion around its center.
The moment of inertia for a uniform disk is given by the formula I (1/2) m r2, where m is the mass of the disk and r is the radius of the disk.
It can be done, but it would require taking an integral for the moment of inertia of each particle of the disc... something i don't have the time to do right now ^^;
The solid disk has a greater moment of inertia than the solid sphere because the mass of the disk is distributed farther from the axis of rotation, resulting in a larger rotational inertia. This difference can be explained by the parallel axis theorem, which states that the moment of inertia of an object can be calculated by adding the moment of inertia of the object's center of mass and the product of the mass and the square of the distance between the center of mass and the axis of rotation.
The moment of inertia of a hollow disk is given by (1/2) * m * (r_outer^2 + r_inner^2), where m is the mass of the disk, r_outer is the outer radius, and r_inner is the inner radius. This formula accounts for the distribution of mass around the central axis of the disk.
The moment of inertia of the compact disk will increase by a factor of 4 (2 raised to the power of 2) when its diameter is doubled while maintaining the same thickness. This is because moment of inertia is proportional to the square of the radius.
The answer will depend on whether the axis isthrough the centre of the disk and perpendicular to its plane,a diameter of the disk, orsome other axis.Unless that information is provided, the answer is meaningless.
To calculate the moment of inertia for an object, you need to know its mass distribution and shape. The formula for moment of inertia varies depending on the shape of the object. For simple shapes like a rod or a disk, there are specific formulas to use. For more complex shapes, you may need to use integration to calculate the moment of inertia.
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If the moment of inertia is five times larger while the angular speed is five times smaller, then the kinetic energy of the spinning disk would decrease. This is because kinetic energy is directly proportional to both the moment of inertia and the square of the angular speed. The decrease in angular speed would have a greater impact on reducing the kinetic energy compared to the increase in moment of inertia.
The moment of inertia of an elliptical disk is given by the formula: I = m(a^2 + b^2)/4, where m is the mass of the disk, a is the semi-major axis, and b is the semi-minor axis. This formula assumes that the disk is rotating around its axis perpendicular to its plane.