The answer will depend on whether the axis is
Unless that information is provided, the answer is meaningless.
0.5 times m times r squared. You can find the moment of inertia of different common shapes in Wikipedia, article "List of moments of inertia".
(pi/2)*(ro^4-ri^4)
The moment of inertia of a hollow cylinder can be calculated with the help of the formula, I=0.5xMxRxR. Here I is inertia, M is mass and R is the radius.
Ans : By the formula of moment of inertia , I=mr2 (2=square) As by the formula it is clear that the moment of inertia depends on the mass and the radius of a particular body , so as the mass increases moment of inertia will considerably increase , So as the water drips into the beaker the mass of the beaker will increase By the law of conservation of angular momentum Moment of inertia is inversely proportional to the angular velocity ( omega ) , Since in the above case of coasting rotating system moment of inertia is increased so the angular velocity (omega) will also decrease and hence the coasting rotating system will now rotate slowly as compared to its rotation before dripping water !
.00288 kgm^2
Mass and radius
mass, velocity and radius
It can be done, but it would require taking an integral for the moment of inertia of each particle of the disc... something i don't have the time to do right now ^^;
The moment of inertia of a hollow cylinder can be calculated with the help of the formula, I=0.5xMxRxR. Here I is inertia, M is mass and R is the radius.
Ans : By the formula of moment of inertia , I=mr2 (2=square) As by the formula it is clear that the moment of inertia depends on the mass and the radius of a particular body , so as the mass increases moment of inertia will considerably increase , So as the water drips into the beaker the mass of the beaker will increase By the law of conservation of angular momentum Moment of inertia is inversely proportional to the angular velocity ( omega ) , Since in the above case of coasting rotating system moment of inertia is increased so the angular velocity (omega) will also decrease and hence the coasting rotating system will now rotate slowly as compared to its rotation before dripping water !
the moment of inertia of a solid cylinder about an axis passing through its COM and parallel to its length is mr2/2 where r is the radius.
mass moment of inertia for a solid sphere: I = (2 /5) * mass * radius2 (mass in kg, radius in metres)
(1/2)mr^2 where m=mass r=radius
I believe it is I = mk^2 where k is radius of gyration and m is mass.
.00288 kgm^2
It is the square root of ratio moment of inertia of the given axis to its mass.
Its diameter is 2R, whatever the mass.
If an ellipse has a radius A long the x-axis and B along the y-axis (A > B) then the moment of inertia about the x-axis is 0.25*pi*ab^3
radius of gyration = sqrt(Moment of inertia/cross section area) Regards, Sumit