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You like the old units! I'll work in SI then give you the answer in BTU. Specific heat capacity of lead = 0.127 KJ.Kg-1.C-1 (kilojoules per kilogram per deg C). 45 lb = 20.41 kg.

100 - 62 = 38 deg F = 21.11 degC.

So heat energy = 0.127 x 20.41 x 21.11 = 54.72 KJ. 1 KJ = 0.9478 BTU

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Related Questions

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