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What are the equations for each of the following radioactive decay reactions alpha emissions by thorium 228 and beta emissions by aluminum 28?
Wiki User
∙ 12y ago
228Th-------------224Ra + α
28Al---------------28Si + β-
Wiki User
∙ 12y ago
The equation for alpha decay of thorium-228 is 228Th -> 224Ra + 4He, where thorium-228 decays into radium-224 by emitting an alpha particle (helium nucleus). The equation for beta decay of aluminum-28 is 28Al -> 28Si + e + v, where aluminum-28 decays into silicon-28 by emitting a beta particle (electron) and an antineutrino.
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