The maximum torque occurs at somewhat lower speed than the full-load working speed of the motor, probably about 50% more than the torque at full power.
Assuming that the motor is a 2-pole one that runs at 90-95% of the synchronous speed, 3000 rpm on 50 Hz or 3600 rpm on 60 Hz, the amount of torque is proportional to the power of the motor.
In SI units the mechanical power equals the torque times the angular velocity, so watts = torque in Newton-metres times speed in radians per second (2.pi radians is one revolution).
So the main factor that determines maximum torque is the rated power of the motor. Double the power, double the torque for a motor running on a constant-frequency power system.
Torque is a measure of twisting force about an Axis. Therefore the factors affecting it are:
1. Length of the wrench from the bolt's center to the point of force application.
2. Amount of force applied Perpendicularly to the wrench's handle.
Note that while the bolt is rotating you can only generate as much torque as is required to overcome its resistance to motion. When the bolt is "set" you can generate enough torque to eventually shear off the bolt!
1.Weight of the body
2.Perpendicular distance
22
That depends on where the axis of rotation is.
Enough to counter the torque from the main rotor. How much that is depends on the helicopter in question - a Blackhawk needs less tail rotor torque than a CH-53E.
The two factors pressure depends on is force and area.
It sort of depends on the muscle and the length of the "lever".
The two factors that govern the torque or turning moment are her mass and the horizontal distance from the seesaw centre to her centre of gravity.
It is not really answerable, depends on many factors. Bolt size thread pitch of the bolt material the bolt is made of that material the bolt is screwed into lubricated/unlubricated and what with what it was initially torqued to If you have Snap on tech100/250 torque wrench it will give you a final torque #, I have seen torque readings double the intial torque # after the 90 degrees.
torque
Depends on other factors such as compression, head port, etc. My 06 Fatboy put out 105 torque, 103 horsepower. Could have gotten more with bigger injectors, but I was fine with results.
Depends WHICH engine, all 2.4's don't have same torque.
it all depends on the mechanics of the car....horsepower, torque, and weight of the vehicle along with several other statistics are all factors in this equation
what you have to understand is that there are many different factors that come into play with this question. it completely depends on the amount of pounds of torque that the engine displaces. so there is no set speed.
It really depends on many factors. some factors include tire diameter, The gross weight of the car, the engine rpm, the way you gear it and whether you used a torque converter or clutch. There are too many factors that you have not included in your question for me to give you an answer. you can gear your engine for more speed and less torque, or you can gear it for more torque and less speed. Torque allows you to accelerate faster but you wont be able to reach a the same max speed as if you geared it for speed. if you solely want speed and you are on a flat paved surface, a clutch would allow more speed, but if you're planning on riding really any other area then you would want a torque converter or else you will blow your clutch.
That depends on what engine it has.
This depends on what engine you are working on.
Depends on the engine.
The answer depends on why you found the factors.
Depends on which engine the car has...