As light passes from air into a glass prism, its velocity decreases due to the change in medium. The frequency of light remains the same as it is determined by the source of the light. The wavelength of light decreases as it enters the denser medium of the glass, causing the light to bend or refract.
If the velocity of a moving particle is reduced to half, the wavelength associated with it will remain the same. The wavelength of a particle is determined by its momentum, not its velocity.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
That doesn't happen. You're fishing for "frequency increases", because you're unclear on the independent and dependent quantities. Once the wave leaves the source, the frequency doesn't change.
If the frequency of a wave is left unchanged, the wavelength will also remain constant. Wavelength and frequency are inversely proportional, so they always adjust together to maintain the speed of the wave.
If the frequency is decreased, the wavelength will increase. This is because the wavelength and frequency of a wave are inversely proportional to each other according to the wave equation λ = c/f, where λ is the wavelength, c is the speed of light, and f is the frequency.
Assuming an electromechanical wave not much. The speed of the wave depends on the medium that the wave is passing through. In a vacuum it is the speed of light, through something else a lesser speed. The wavelength stays the same and the frequency stays the same.
This generally happens when a wave moves from one medium into another.Now, the velocity (v) of a wave (mechanical and electromagnetic) is equal to the product of its frequency (f) and wavelength (λ).So, v = f x λThat means if frequency is constant, the wavelength is directly proportional to the velocity.So, if the speed of the wave increases (while frequency remains the same), the wavelength will also increase.
If the velocity of a moving particle is reduced to half, the wavelength associated with it will remain the same. The wavelength of a particle is determined by its momentum, not its velocity.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
Whatever the wavelength and frequency happen to be, their product is always equal to the speed.
That doesn't happen. You're fishing for "frequency increases", because you're unclear on the independent and dependent quantities. Once the wave leaves the source, the frequency doesn't change.
It would change, depending on how much the frequency and the wavelength changes. It varies based on v = fλ.
If the frequency of a wave is left unchanged, the wavelength will also remain constant. Wavelength and frequency are inversely proportional, so they always adjust together to maintain the speed of the wave.
If the frequency is decreased, the wavelength will increase. This is because the wavelength and frequency of a wave are inversely proportional to each other according to the wave equation λ = c/f, where λ is the wavelength, c is the speed of light, and f is the frequency.
IF a wave moving at a constant speed were to have it's wavelength doubled (Wavelength x 2), then the frequency of the wave would be half of what it originally was (Frequency / 2).
Changing the amplitude of a wave does not affect its wavelength. Wavelength is the distance between corresponding points on a wave and is determined by the frequency of the wave and the speed at which it travels through a medium. Amplitude, on the other hand, represents the height of the wave and does not impact the wavelength.
If you increase the frequency of a periodic wave, the wavelength would decrease. This is because wavelength and frequency are inversely proportional in a wave: as frequency goes up, wavelength goes down.