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The force between the two charges increases 16 times.

Coulomb's law equation states:

│F│ = ke │q1q2│/r2

Where (F) is the force acting simultaneously on both point charges (q1) and (q2).

r is the separation distance and ke is a proportionality constant called the Coulomb

constant.

Using above equation, if we double both charges and reduce the distance in half.

│F2│ = ke │(2q12q2)│/(r/2)2 = 16 ke │q1q2│/r2 = 16 │F│.

We see that the force turns out 16 times stronger

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Maude Kulas

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3y ago

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What happens to the force between two charges if the magnitude of both charges is doubled and the distance between them is double?

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