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What is the magnitude of resultant force in case of concurrent forces in equilibrium?
In the case of concurrent forces in equilibrium, the magnitude of the resultant force is zero. This means that the forces are balanced and cancel each other out, resulting in no net force acting on the object.
What is the resultant magnitude of 6N force acting at right angle to a 8N force?
The magnitude of the resultant force is found using the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. In this case, the resultant force is √(6^2 + 8^2) = √(36 + 64) = √100 = 10N.
Does torque and work are equivalent?
Torque is rotational force, while work is energy transferred between objects. For example, a screw experiences mostly torque as you twist it around its axis, while a nail experiences mostly work as it is driven straight into the wood.
Can a body in free fall in equilibrium?
Assuming that the question is "Can a body in free fall be in equilibrium?" A system (or body) is said to be in equilibrium if there is no net force and no net torque (turning effect produced by the forces). a net force means that no resulting force is acting on the object. The force of the body (according to Newton's second law of motion F=MA) is the product of the mass of the object and its acceleration. In this case, the object's acceleration would be the acceleration of free fall. Applying this in the context of this question: As soon as the fluid resistance (air resistance) is equal and opposite to the weight of the body (it's force according to the product of its mass and acceleration); the object has no resultant force. However, the body is still travelling towards the centre of the gravitational field (If it was a planet, it would be the centre of the planet) and as you travel towards the centre of the gravitational field, the acceleration due to free-fall increases according to the law of gravitation attraction. This would resultant in more force (and thus weight) and air resistance would have to be equal and opposite to result in no net force acting on the body. According to the law of gravitational attraction, the force (weight of an object) is governed by the product of the gravitational constant and the mass of the 2 objects involved and all this divided by the square of the distance between them. Applying this to the question, the body's force increases the closer it gets to the object it is going towards. So it may not be easily possible to achieve a zero net force in which the object does not accelerate. However, the other criteria for equilibrium is that there is no net torque (no resultant turning effect of the forces on the body). So long as the object does not rotate or turn then there is no resultant torque. In conclusion, a body in free fall can only be in free fall if it has no resultant force. No resultant force can only be achieved inside a fluid (something that flows like a gas or liquid) to stop the object from accelerating. If it is inside a fluid, fluid resistance will eventually equal the weight of the object and will result in no resultant force acting. However, in space (assuming that the gravitational attraction of the body that you are going towards is still acting), the body will not encounter fluid resistance so it will continue to speed up according to the acceleration of free-fall and it will have a resultant force. The other criteria for equilibrium is no resultant torque; so long as the object does not rotate, it has no resultant torque. So if the object is in space and still under the influence of the gravitational field the body is accelerating towards, it is not in equilibrium as it has a resultant force. But if it is inside a fluid and is encountering an equal but opposite force and results in a zero net force and zero net torque...it is in a state of equilibrium
Two men applaying forces in different direction on a stone of 30kg and 5 healthy men applaying full force on the same and determining resultant reaction?
If the two men are applying forces in different directions on the stone, the resultant force will depend on the magnitudes and directions of the individual forces. If the 5 healthy men are applying a combined force in one direction, their collective force will determine the resultant reaction on the stone. The resultant reaction will be the sum of all the forces acting on the stone, taking into account both magnitude and direction.
Give an example of a case when the resultant force is zero but resultant torque is not zero?
A couple.
What is the magnitude of resultant force in case of concurrent force in equilibrium?
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
If a book is pushed by 10N and the friction is 8N what is the resultant force?
In fact, there is an infinite number of answers because force is a vector, meaning that it has a magnitude and an orientation. For example, if someone pushes horizontaly onto the book (10N) and the friction is 8N in the opposite direction, the resultant force is 2N. But if the book is pushed at an angle, the resultant force changes.
What is the magnitude of resultant force in case of concurrent forces in equilibrium?
In the case of concurrent forces in equilibrium, the magnitude of the resultant force is zero. This means that the forces are balanced and cancel each other out, resulting in no net force acting on the object.
How do i calculate the torque of an engine?
Torque is defined as force multiplied by the distance, from the axis of rotation, at which such as force is applied.In the case of an engine, I believe the torque would have to be measured.
What is the resultant magnitude of 6N force acting at right angle to a 8N force?
The magnitude of the resultant force is found using the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. In this case, the resultant force is √(6^2 + 8^2) = √(36 + 64) = √100 = 10N.
Does torque and work are equivalent?
Torque is rotational force, while work is energy transferred between objects. For example, a screw experiences mostly torque as you twist it around its axis, while a nail experiences mostly work as it is driven straight into the wood.
What is the formula for torque?
t = r X F, where t is torque, r is displacement, and F is force; all quantities are vectors. Because the formula contains a cross product, the magnitude of the torque is given by the expression rFsin(θ), where θ is the angle between the position vector and the force vector.
What is a torque meter?
A torque sensor, or torque meter, is a device that measures the torque on rotating systems, usually wheels. Torque, in this case, is the twisting force that causes rotation, such as that applied when you pedal a bicycle.
When A force of 5 newton is acting parallel to the moment arm of 10 cm . so what is torque?
In order for a force to produce a torque, either all of it, or a part of it (component) must act perpendicular to the moment arm. If, as in your case, all of the force is parallel to the moment arm then the force can not produce a torque. So the answer is; the torque is zero.
Can a body in free fall in equilibrium?
Assuming that the question is "Can a body in free fall be in equilibrium?" A system (or body) is said to be in equilibrium if there is no net force and no net torque (turning effect produced by the forces). a net force means that no resulting force is acting on the object. The force of the body (according to Newton's second law of motion F=MA) is the product of the mass of the object and its acceleration. In this case, the object's acceleration would be the acceleration of free fall. Applying this in the context of this question: As soon as the fluid resistance (air resistance) is equal and opposite to the weight of the body (it's force according to the product of its mass and acceleration); the object has no resultant force. However, the body is still travelling towards the centre of the gravitational field (If it was a planet, it would be the centre of the planet) and as you travel towards the centre of the gravitational field, the acceleration due to free-fall increases according to the law of gravitation attraction. This would resultant in more force (and thus weight) and air resistance would have to be equal and opposite to result in no net force acting on the body. According to the law of gravitational attraction, the force (weight of an object) is governed by the product of the gravitational constant and the mass of the 2 objects involved and all this divided by the square of the distance between them. Applying this to the question, the body's force increases the closer it gets to the object it is going towards. So it may not be easily possible to achieve a zero net force in which the object does not accelerate. However, the other criteria for equilibrium is that there is no net torque (no resultant turning effect of the forces on the body). So long as the object does not rotate or turn then there is no resultant torque. In conclusion, a body in free fall can only be in free fall if it has no resultant force. No resultant force can only be achieved inside a fluid (something that flows like a gas or liquid) to stop the object from accelerating. If it is inside a fluid, fluid resistance will eventually equal the weight of the object and will result in no resultant force acting. However, in space (assuming that the gravitational attraction of the body that you are going towards is still acting), the body will not encounter fluid resistance so it will continue to speed up according to the acceleration of free-fall and it will have a resultant force. The other criteria for equilibrium is no resultant torque; so long as the object does not rotate, it has no resultant torque. So if the object is in space and still under the influence of the gravitational field the body is accelerating towards, it is not in equilibrium as it has a resultant force. But if it is inside a fluid and is encountering an equal but opposite force and results in a zero net force and zero net torque...it is in a state of equilibrium
Is torque independent of location of axis?
No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)
