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What is An example of case when resultant force is zero but torque is not zero?
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What is the magnitude of resultant force in case of concurrent forces in equilibrium?
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
Does torque and work are equivalent?
Torque is rotational force, while work is energy transferred between objects. For example, a screw experiences mostly torque as you twist it around its axis, while a nail experiences mostly work as it is driven straight into the wood.
Can a body in free fall in equilibrium?
Assuming that the question is "Can a body in free fall be in equilibrium?" A system (or body) is said to be in equilibrium if there is no net force and no net torque (turning effect produced by the forces). a net force means that no resulting force is acting on the object. The force of the body (according to Newton's second law of motion F=MA) is the product of the mass of the object and its acceleration. In this case, the object's acceleration would be the acceleration of free fall. Applying this in the context of this question: As soon as the fluid resistance (air resistance) is equal and opposite to the weight of the body (it's force according to the product of its mass and acceleration); the object has no resultant force. However, the body is still travelling towards the centre of the gravitational field (If it was a planet, it would be the centre of the planet) and as you travel towards the centre of the gravitational field, the acceleration due to free-fall increases according to the law of gravitation attraction. This would resultant in more force (and thus weight) and air resistance would have to be equal and opposite to result in no net force acting on the body. According to the law of gravitational attraction, the force (weight of an object) is governed by the product of the gravitational constant and the mass of the 2 objects involved and all this divided by the square of the distance between them. Applying this to the question, the body's force increases the closer it gets to the object it is going towards. So it may not be easily possible to achieve a zero net force in which the object does not accelerate. However, the other criteria for equilibrium is that there is no net torque (no resultant turning effect of the forces on the body). So long as the object does not rotate or turn then there is no resultant torque. In conclusion, a body in free fall can only be in free fall if it has no resultant force. No resultant force can only be achieved inside a fluid (something that flows like a gas or liquid) to stop the object from accelerating. If it is inside a fluid, fluid resistance will eventually equal the weight of the object and will result in no resultant force acting. However, in space (assuming that the gravitational attraction of the body that you are going towards is still acting), the body will not encounter fluid resistance so it will continue to speed up according to the acceleration of free-fall and it will have a resultant force. The other criteria for equilibrium is no resultant torque; so long as the object does not rotate, it has no resultant torque. So if the object is in space and still under the influence of the gravitational field the body is accelerating towards, it is not in equilibrium as it has a resultant force. But if it is inside a fluid and is encountering an equal but opposite force and results in a zero net force and zero net torque...it is in a state of equilibrium
What are the examples of moment of force?
The moment of a force is the multiple of the force and the distance from the point of application. An example is in tightening wheel nuts. The torque spanner used has a calibration in ft.lb or Newton.meters, so that the correct tightening torque is applied. If the shaft was made twice as long, the necessary force at the shaft end would be half as much. The concept of energy E= fd = -f.d + fxd where f is vector force and d is vector displacement. Energy is a quaternion consisting of a real and three vectors.Work is the real moment of force w= -f.d and Torque is the vector moment of force t=fxd.
Why torque is zero when force is applied to point that passes through pivot point?
Torque is defined as the product of the distance from the pivot point, times a force, times an angle function. If any of the three factors is zero, the product is zero. In this case, the distance from the pivot point.
Give an example of a case when the resultant force is zero but resultant torque is not zero?
A couple.
What is the magnitude of resultant force in case of concurrent force in equilibrium?
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
What is the magnitude of resultant force in case of concurrent forces in equilibrium?
The magnitude of the resultant force in the case of the concurrent forces in equilibrium.
How do i calculate the torque of an engine?
Torque is defined as force multiplied by the distance, from the axis of rotation, at which such as force is applied.In the case of an engine, I believe the torque would have to be measured.
Does torque and work are equivalent?
Torque is rotational force, while work is energy transferred between objects. For example, a screw experiences mostly torque as you twist it around its axis, while a nail experiences mostly work as it is driven straight into the wood.
What is the formula for torque?
t = r X F, where t is torque, r is displacement, and F is force; all quantities are vectors. Because the formula contains a cross product, the magnitude of the torque is given by the expression rFsin(θ), where θ is the angle between the position vector and the force vector.
What is a torque meter?
A torque sensor, or torque meter, is a device that measures the torque on rotating systems, usually wheels. Torque, in this case, is the twisting force that causes rotation, such as that applied when you pedal a bicycle.
When A force of 5 newton is acting parallel to the moment arm of 10 cm . so what is torque?
In order for a force to produce a torque, either all of it, or a part of it (component) must act perpendicular to the moment arm. If, as in your case, all of the force is parallel to the moment arm then the force can not produce a torque. So the answer is; the torque is zero.
Is torque independent of location of axis?
No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)No, the axis must be specified: torque = (distance from the axis) X (force). (X is the vector cross-product in this case - meaning the angle also matters.)
Newton's first law is a special case of the second law Explain?
Newton's second law states that the rate of change of momentum of a body is equal to the resultant force on the body and is in the same direction as the resultant force. Thus, it also implies that when the resultant force on a body is zero, the rate of change of momentum is zero, and if it concerns a body of constant mass, the acceleration is zero. This is Newton's first law, which states that 'any body continues in its state of rest or uniform motion in a straight line unless a resultant force acts on it to cause it to accelerate'.
Can a body in free fall in equilibrium?
Assuming that the question is "Can a body in free fall be in equilibrium?" A system (or body) is said to be in equilibrium if there is no net force and no net torque (turning effect produced by the forces). a net force means that no resulting force is acting on the object. The force of the body (according to Newton's second law of motion F=MA) is the product of the mass of the object and its acceleration. In this case, the object's acceleration would be the acceleration of free fall. Applying this in the context of this question: As soon as the fluid resistance (air resistance) is equal and opposite to the weight of the body (it's force according to the product of its mass and acceleration); the object has no resultant force. However, the body is still travelling towards the centre of the gravitational field (If it was a planet, it would be the centre of the planet) and as you travel towards the centre of the gravitational field, the acceleration due to free-fall increases according to the law of gravitation attraction. This would resultant in more force (and thus weight) and air resistance would have to be equal and opposite to result in no net force acting on the body. According to the law of gravitational attraction, the force (weight of an object) is governed by the product of the gravitational constant and the mass of the 2 objects involved and all this divided by the square of the distance between them. Applying this to the question, the body's force increases the closer it gets to the object it is going towards. So it may not be easily possible to achieve a zero net force in which the object does not accelerate. However, the other criteria for equilibrium is that there is no net torque (no resultant turning effect of the forces on the body). So long as the object does not rotate or turn then there is no resultant torque. In conclusion, a body in free fall can only be in free fall if it has no resultant force. No resultant force can only be achieved inside a fluid (something that flows like a gas or liquid) to stop the object from accelerating. If it is inside a fluid, fluid resistance will eventually equal the weight of the object and will result in no resultant force acting. However, in space (assuming that the gravitational attraction of the body that you are going towards is still acting), the body will not encounter fluid resistance so it will continue to speed up according to the acceleration of free-fall and it will have a resultant force. The other criteria for equilibrium is no resultant torque; so long as the object does not rotate, it has no resultant torque. So if the object is in space and still under the influence of the gravitational field the body is accelerating towards, it is not in equilibrium as it has a resultant force. But if it is inside a fluid and is encountering an equal but opposite force and results in a zero net force and zero net torque...it is in a state of equilibrium
What is it called when the direction of more than one force acting on an object give a net force unequal to zero?
In that case, the forces are said to be unbalanced.
