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Surface deliberately made to ease the calculation of the electric flux for detemination of Electric field from gauss's law.
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Why is electric field inside a ring is zero?
If you refer to Gauss's law, it states the electric flux through any closed surface is proportionate to the enclosed electric charge. The electric flux density is the same as the electric field intensity. A Gaussian surface is a closed, three dimensional surface (there's no holes in it). Here's an example to help clarify what this is and is not saying. Suppose I have a clear glass ball. The "light charge" inside the ball is zero because there is no light source inside the ball. If I put the ball in the sunlight, light will go into one side, and out the other (ignore any sort of prism effect, etc. just don't think too hard about this example!). This ball still does not have an internal "light charge" because the light flowing into the ball is equivalent to the light flowing out (the "light density" through the surface sums to zero, or the line integral of the light density = 0 for this surface). If I put a light source inside the ball, the line integral of "light density" leaving the ball would be proportional to the "light charge" inside the ball; in other words the line integral tells you what is enclosed by the Gaussian surface (my fictitious light source, but not the sun). Even if I put it in the sunlight again, the line integral will remove the "light charge" due to the sun and I will be left with only my internal light source. In both these instances, absolutely nothing is being stated about the "light density" / "light intensity" inside the ball. For both instances, there is a light intensity INSIDE the ball, even though the "light charge" inside is non zero in only one case. Relating to the question, this means if you have a Gaussian surface (such as a sphere), and it has/does not have an enclosed electric charge, you can have an electric field through the sphere - the fact this field is there tells you nothing about the internal charge of the Gaussian surface until you perform the line integral to measure what's coming in and what's going out. So, what I'm stating is the question is not true - the electric field is not necessarily zero inside a Gaussian surface, even if the surface does not contain an electrically charged particle. This should be easily seen by taking the typical point charge example: You have a point charge, and you draw the Gaussian surface around it. The point charge radiates electric field lines in all directions away from itself. If you move the Gaussian surface to the left until the point charge is no longer enclosed in it, you will see the radiating electric field lines due to this point charge still go into and out of the surface (so there is an electric field due to the point charge inside the surface), but the point charge is no longer enclosed by the surface (so the line integral sums to zero).
What do you mean by Gaussian noise?
Gaussian noise is similar to white noise, but it falls within a narrower range of frequencies. In communications, it is produced by the movement of electricity through the line. You see and hear that when you have your television on an empty channel. Within photos and videos, Gaussian noise is in the form of random patterns, and this is what makes things look slightly blurry.
What is the difference between white noise and gaussian noise?
for a white noise the psd is flat i.e the distribution of energy over central freq is 1 and for gaussian noise as the name says the psd is normally distributed.
Is the force is greater on a smooth surface or on a rough surface?
smooth surface.
Need the mathematics to show gaussian border with radiators and a time varying field equals Maxwells law?
I suggest you Google it or log onto Physics.org. If only it was that easy.I doubt that anybody has ever done it! Both are in different units for a start
A Gaussian surface does not enclose a charge Does it mean that E equals 0 on its surface?
No.there can be electric field on the Gaussian surface even if the charge enclosed by it is zero.However ,net flux will be zero through the surface.
What is the advantage of using Gauss's law in the field of physics instead of using Coulomb's?
Gauss' law can be used quite easily to find the net field through a gaussian surface, or any body, by cleverly constructing a suitable gaussian surface. The net field is equal to the charge enclosed within the gaussian surface divided by the permittivity of the medium through which field is calculated.
What is gaussian filter in term of image processing?
the gaussian filter is also known as Gaussian smoothing and is the result of blurring an image by a Gaussian function.
What do you mean by gaussian?
The Gaussian distribution is the same as the normal distribution. Sometimes, "Gaussian" is used as in "Gaussian noise" and "Gaussian process." See related links, Interesting that Gauss did not first derive this distribution. That honor goes to de Moivre in 1773.
Autocorrelation Characteristics of Super-Gaussian Optical Pulse?
autocorrelation characteristics of super gaussian optical pulse with gaussian optical pulse.
How do you get symmetric Gaussian curve?
when the signals are symmetric then this signals are gaussian In statistics, the Gaussian curve, also known as the Normal curve, is symmetrical.
What is the difference between white Gaussian noise and additive white Gaussian noise?
A Gaussian noise is a type of statistical noise in which the amplitude of the noise follows that of a Gaussian distribustion whereas additive white Gaussian noise is a linear combination of a Gaussian noise and a white noise (white noise has a flat or constant power spectral density).
Where can one get a Gaussian Copula?
There are many places where one can get a Gaussian Copula. One can get a Gaussian Copula at popular on the web sources such as Wired, UCL Finds, and SPS.
What four shapes have formulas which include the symbol pi?
A circle,An ellipse, A sphere,A normal (Gaussian) distribution.A circle,An ellipse, A sphere,A normal (Gaussian) distribution.A circle,An ellipse, A sphere,A normal (Gaussian) distribution.A circle,An ellipse, A sphere,A normal (Gaussian) distribution.
Which is more efficient for solving linear systems gaussian elimination or cramer's rule?
Of course, Gaussian Elimination!
What is Gaussian Model?
The Gaussian probability density distribution (pdf) is referred to as the Normal distribution. The Gaussian model results in a Gaussian pdf. Interesting, it didn't come from Gauss, but de Moivre, one of the greatest mathematicians of the 18th century, at least in my opinion. See related links.
Why is the normal probability distribution called a family of normal probability distribution?
Because very many variables tend to have the Gaussian distribution. Furthermore, even if the underlying distribution is non-Gaussian, the distribution of the means of repeated samples will be Gaussian. As a result, the Gaussian distributions are also referred to as Normal.
