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If more electric field lines are leaving a gaussian surface than entering what can you conclude about the net charge enclosed by that surface?
If more electric field lines are leaving a Gaussian surface than entering, this indicates that there is a net positive charge enclosed by the surface. According to Gauss's Law, the total electric flux through a closed surface is directly proportional to the net charge enclosed by that surface.
What else can I help you with?
What is the electric field inside a Gaussian cylinder?
The electric field inside a Gaussian cylinder is zero.
In which direction is the electric field on the cylindrical Gaussian surface oriented?
The electric field on the cylindrical Gaussian surface is oriented perpendicular to the surface, pointing outward or inward depending on the charge distribution inside the surface.
How can Gauss's law be utilized to determine an expression for the electric field strength within a slab?
Gauss's law can be used to find the electric field strength within a slab by considering a Gaussian surface that encloses the slab. By applying Gauss's law, which relates the electric flux through a closed surface to the charge enclosed by that surface, one can derive an expression for the electric field strength within the slab.
What is Gaussian Surface?
A Gaussian surface is an imaginary closed surface used in Gauss's law to calculate the electric field or flux through the surface. It is often chosen to simplify the calculation by taking advantage of the symmetry of the system.
How to find the electric field at a point in a given system?
To find the electric field at a point in a given system, you can use Coulomb's law or Gauss's law. Coulomb's law involves calculating the electric field due to individual charges in the system, while Gauss's law allows you to find the electric field by considering the total charge enclosed by a Gaussian surface around the point of interest. By applying these principles, you can determine the electric field strength and direction at a specific point in the system.
A Gaussian surface does not enclose a charge Does it mean that E equals 0 on its surface?
No.there can be electric field on the Gaussian surface even if the charge enclosed by it is zero.However ,net flux will be zero through the surface.
What is the electric field inside a Gaussian cylinder?
The electric field inside a Gaussian cylinder is zero.
In which direction is the electric field on the cylindrical Gaussian surface oriented?
The electric field on the cylindrical Gaussian surface is oriented perpendicular to the surface, pointing outward or inward depending on the charge distribution inside the surface.
How can Gauss's law be utilized to determine an expression for the electric field strength within a slab?
Gauss's law can be used to find the electric field strength within a slab by considering a Gaussian surface that encloses the slab. By applying Gauss's law, which relates the electric flux through a closed surface to the charge enclosed by that surface, one can derive an expression for the electric field strength within the slab.
What is the total flux across a gaussian sphere enclosing an electric dipole?
The total flux across a Gaussian sphere enclosing an electric dipole is zero. This is because the electric field lines originating from the positive charge of the dipole cancel out the electric field lines terminating at the negative charge within the sphere, resulting in a net flux of zero according to Gauss's Law.
What is Gaussian Surface?
A Gaussian surface is an imaginary closed surface used in Gauss's law to calculate the electric field or flux through the surface. It is often chosen to simplify the calculation by taking advantage of the symmetry of the system.
How to find the electric field at a point in a given system?
To find the electric field at a point in a given system, you can use Coulomb's law or Gauss's law. Coulomb's law involves calculating the electric field due to individual charges in the system, while Gauss's law allows you to find the electric field by considering the total charge enclosed by a Gaussian surface around the point of interest. By applying these principles, you can determine the electric field strength and direction at a specific point in the system.
What is gaussian filter in term of image processing?
the gaussian filter is also known as Gaussian smoothing and is the result of blurring an image by a Gaussian function.
Why is electric field inside a ring is zero?
If you refer to Gauss's law, it states the electric flux through any closed surface is proportionate to the enclosed electric charge. The electric flux density is the same as the electric field intensity. A Gaussian surface is a closed, three dimensional surface (there's no holes in it). Here's an example to help clarify what this is and is not saying. Suppose I have a clear glass ball. The "light charge" inside the ball is zero because there is no light source inside the ball. If I put the ball in the sunlight, light will go into one side, and out the other (ignore any sort of prism effect, etc. just don't think too hard about this example!). This ball still does not have an internal "light charge" because the light flowing into the ball is equivalent to the light flowing out (the "light density" through the surface sums to zero, or the line integral of the light density = 0 for this surface). If I put a light source inside the ball, the line integral of "light density" leaving the ball would be proportional to the "light charge" inside the ball; in other words the line integral tells you what is enclosed by the Gaussian surface (my fictitious light source, but not the sun). Even if I put it in the sunlight again, the line integral will remove the "light charge" due to the sun and I will be left with only my internal light source. In both these instances, absolutely nothing is being stated about the "light density" / "light intensity" inside the ball. For both instances, there is a light intensity INSIDE the ball, even though the "light charge" inside is non zero in only one case. Relating to the question, this means if you have a Gaussian surface (such as a sphere), and it has/does not have an enclosed electric charge, you can have an electric field through the sphere - the fact this field is there tells you nothing about the internal charge of the Gaussian surface until you perform the line integral to measure what's coming in and what's going out. So, what I'm stating is the question is not true - the electric field is not necessarily zero inside a Gaussian surface, even if the surface does not contain an electrically charged particle. This should be easily seen by taking the typical point charge example: You have a point charge, and you draw the Gaussian surface around it. The point charge radiates electric field lines in all directions away from itself. If you move the Gaussian surface to the left until the point charge is no longer enclosed in it, you will see the radiating electric field lines due to this point charge still go into and out of the surface (so there is an electric field due to the point charge inside the surface), but the point charge is no longer enclosed by the surface (so the line integral sums to zero).
What do you mean by gaussian?
The Gaussian distribution is the same as the normal distribution. Sometimes, "Gaussian" is used as in "Gaussian noise" and "Gaussian process." See related links, Interesting that Gauss did not first derive this distribution. That honor goes to de Moivre in 1773.
What are the fundamental differences between Gaussian units and SI units in the context of electromagnetic theory?
In the context of electromagnetic theory, the fundamental differences between Gaussian units and SI units lie in the way they define the basic electromagnetic quantities such as electric charge, electric field, magnetic field, and current. Gaussian units are based on the electrostatic unit of charge, while SI units are based on the coulomb. This leads to differences in the equations and constants used in electromagnetic theory calculations.
Autocorrelation Characteristics of Super-Gaussian Optical Pulse?
autocorrelation characteristics of super gaussian optical pulse with gaussian optical pulse.
