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If you refer to Gauss's law, it states the electric flux through any closed surface is proportionate to the enclosed electric charge.
The electric flux density is the same as the electric field intensity. A Gaussian surface is a closed, three dimensional surface (there's no holes in it).
Here's an example to help clarify what this is and is not saying. Suppose I have a clear glass ball. The "light charge" inside the ball is zero because there is no light source inside the ball. If I put the ball in the sunlight, light will go into one side, and out the other (ignore any sort of prism effect, etc. just don't think too hard about this example!). This ball still does not have an internal "light charge" because the light flowing into the ball is equivalent to the light flowing out (the "light density" through the surface sums to zero, or the line integral of the light density = 0 for this surface).
If I put a light source inside the ball, the line integral of "light density" leaving the ball would be proportional to the "light charge" inside the ball; in other words the line integral tells you what is enclosed by the Gaussian surface (my fictitious light source, but not the sun). Even if I put it in the sunlight again, the line integral will remove the "light charge" due to the sun and I will be left with only my internal light source.
In both these instances, absolutely nothing is being stated about the "light density" / "light intensity" inside the ball. For both instances, there is a light intensity INSIDE the ball, even though the "light charge" inside is non zero in only one case.
Relating to the question, this means if you have a Gaussian surface (such as a sphere), and it has/does not have an enclosed electric charge, you can have an electric field through the sphere - the fact this field is there tells you nothing about the internal charge of the Gaussian surface until you perform the line integral to measure what's coming in and what's going out.
So, what I'm stating is the question is not true - the electric field is not necessarily zero inside a Gaussian surface, even if the surface does not contain an electrically charged particle. This should be easily seen by taking the typical point charge example: You have a point charge, and you draw the Gaussian surface around it. The point charge radiates electric field lines in all directions away from itself. If you move the Gaussian surface to the left until the point charge is no longer enclosed in it, you will see the radiating electric field lines due to this point charge still go into and out of the surface (so there is an electric field due to the point charge inside the surface), but the point charge is no longer enclosed by the surface (so the line integral sums to zero).
What else can I help you with?
Why is electric potential inside a ring conductor on a conducting paper that has elctric field zero?
The electric potential inside a ring conductor on a conducting paper is zero because the electric field inside a conductor in electrostatic equilibrium is zero. This is due to the charges redistributing themselves in such a way that the electric field cancels out inside the conductor. Since the electric potential is directly related to the electric field, the potential inside the conductor is also zero.
Why should the Electric field inside a conductor zero?
The electric field inside a conductor is zero because any electric field that is present will cause the charges inside the conductor to move until they distribute themselves in such a way that cancels out the electric field. This redistribution of charges ensures that the net electric field inside the conductor is zero in equilibrium.
What is the electric field inside a Gaussian cylinder?
The electric field inside a Gaussian cylinder is zero.
What is the difference in the electric field inside and outside a charged insulator?
The electric field inside a charged insulator is zero, while the electric field outside a charged insulator is non-zero.
What is the distribution of the electric field inside a hollow conductor?
The electric field inside a hollow conductor is zero.
Why is electric potential inside a ring conductor on a conducting paper that has elctric field zero?
The electric potential inside a ring conductor on a conducting paper is zero because the electric field inside a conductor in electrostatic equilibrium is zero. This is due to the charges redistributing themselves in such a way that the electric field cancels out inside the conductor. Since the electric potential is directly related to the electric field, the potential inside the conductor is also zero.
Why should the Electric field inside a conductor zero?
The electric field inside a conductor is zero because any electric field that is present will cause the charges inside the conductor to move until they distribute themselves in such a way that cancels out the electric field. This redistribution of charges ensures that the net electric field inside the conductor is zero in equilibrium.
What is the electric field inside a Gaussian cylinder?
The electric field inside a Gaussian cylinder is zero.
What is the difference in the electric field inside and outside a charged insulator?
The electric field inside a charged insulator is zero, while the electric field outside a charged insulator is non-zero.
What is the distribution of the electric field inside a hollow conductor?
The electric field inside a hollow conductor is zero.
Why is the electric field inside a conductor always zero?
The electric field inside a conductor is always zero because the free charges in the conductor rearrange themselves in such a way that they cancel out any external electric field that may be present. This redistribution of charges ensures that the electric field inside the conductor is zero, maintaining electrostatic equilibrium.
What is the distribution of the electric field inside a uniformly charged sphere?
The electric field inside a uniformly charged sphere is zero.
The electrical intensity inside a charged hollow sphere is?
Zero, because the electric field inside a charged hollow sphere is zero. This is due to the Gauss's law and symmetry of the charged hollow sphere, which results in no net electric field inside the sphere.
What is the electric field inside a sphere of uniform charge density?
The electric field inside a sphere of uniform charge density is zero.
What will happened to the strength of electric field inside a shell of charge?
Inside a shell of charge, the electric field strength is zero, regardless of the thickness of the shell or the distribution of charge on it. This is due to the property of electrostatics known as Gauss's Law, which states that the electric field inside a closed surface enclosing a charge distribution is zero.
What is the electric field inside a conductor according to the concept of mastering physics?
According to the concept of mastering physics, the electric field inside a conductor is zero.
What is the distribution of the electric field inside a cavity within a uniformly charged sphere?
The electric field inside a cavity within a uniformly charged sphere is zero.
