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If you refer to Gauss's law, it states the electric flux through any closed surface is proportionate to the enclosed electric charge.

The electric flux density is the same as the electric field intensity. A Gaussian surface is a closed, three dimensional surface (there's no holes in it).

Here's an example to help clarify what this is and is not saying. Suppose I have a clear glass ball. The "light charge" inside the ball is zero because there is no light source inside the ball. If I put the ball in the sunlight, light will go into one side, and out the other (ignore any sort of prism effect, etc. just don't think too hard about this example!). This ball still does not have an internal "light charge" because the light flowing into the ball is equivalent to the light flowing out (the "light density" through the surface sums to zero, or the line integral of the light density = 0 for this surface).

If I put a light source inside the ball, the line integral of "light density" leaving the ball would be proportional to the "light charge" inside the ball; in other words the line integral tells you what is enclosed by the Gaussian surface (my fictitious light source, but not the sun). Even if I put it in the sunlight again, the line integral will remove the "light charge" due to the sun and I will be left with only my internal light source.

In both these instances, absolutely nothing is being stated about the "light density" / "light intensity" inside the ball. For both instances, there is a light intensity INSIDE the ball, even though the "light charge" inside is non zero in only one case.

Relating to the question, this means if you have a Gaussian surface (such as a sphere), and it has/does not have an enclosed electric charge, you can have an electric field through the sphere - the fact this field is there tells you nothing about the internal charge of the Gaussian surface until you perform the line integral to measure what's coming in and what's going out.

So, what I'm stating is the question is not true - the electric field is not necessarily zero inside a Gaussian surface, even if the surface does not contain an electrically charged particle. This should be easily seen by taking the typical point charge example: You have a point charge, and you draw the Gaussian surface around it. The point charge radiates electric field lines in all directions away from itself. If you move the Gaussian surface to the left until the point charge is no longer enclosed in it, you will see the radiating electric field lines due to this point charge still go into and out of the surface (so there is an electric field due to the point charge inside the surface), but the point charge is no longer enclosed by the surface (so the line integral sums to zero).

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I think there is no charge distribution in side a ring

Q: Why is electric field inside a ring is zero?

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it is the magnetic field not the electric field which accelerates the ion inside the dees

As long as there is any electric potential, charges continue moving around, until everything is balanced.

The electric FIELD inside a charged hollow CONDUCTOR is zero.

If the net charge enclosed by a surface is zero then the field at all points on the surface is not zero because gauss's law states that if the charge enclosed by a surface is zero then the flux through the surface is zero which depends upon the magnitude of field and the angle that it makes with the area vector at each point and so it is not necessary that the field will be zero at all points of the surface.

The field is zero inside only if any charge is evenly distributed on the surface. That's a mathematical theorem, sorry I don't have the proof handy. But when you measure the electric field inside a charged sphere, the charge you use might be large enough to redistribute the surface charge. In this case the electric field will not be zero. Only if you measure at the centre.

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it is the magnetic field not the electric field which accelerates the ion inside the dees

As long as there is any electric potential, charges continue moving around, until everything is balanced.

If the charge is uniformly distributed over the shell, then the electric field is zero everywhere inside.

Inside a conductor, it's zero.

The electric FIELD inside a charged hollow CONDUCTOR is zero.

If the net charge enclosed by a surface is zero then the field at all points on the surface is not zero because gauss's law states that if the charge enclosed by a surface is zero then the flux through the surface is zero which depends upon the magnitude of field and the angle that it makes with the area vector at each point and so it is not necessary that the field will be zero at all points of the surface.

electric field inside the conducting sphere is ZER0..! because their are equivalent charges all around the sphere which makes the net force zero hence we can say that the electric field is also zero.!

The field is zero inside only if any charge is evenly distributed on the surface. That's a mathematical theorem, sorry I don't have the proof handy. But when you measure the electric field inside a charged sphere, the charge you use might be large enough to redistribute the surface charge. In this case the electric field will not be zero. Only if you measure at the centre.

The electric flux depends on charge, when the charge is zero the flux is zero. The electric field depends also on the charge. Thus when the electric flux is zero , the electric field is also zero for the same reason, zero charge. Phi= integral E.dA= integral zcDdA = zcQ Phi is zcQ and depends on charge Q, as does E.

1. Electric field lines of force originate from the positive charge and terminate at the negative charge. 2. Electric field lines of force can never intersect each other. 3. Electric field lines of force are not present inside the conductor, it is because electric field inside the conductor is always zero. 4. Electric field lines of force are always perpendicular to the surface of conductor. 5. Curved electric field lines are always non-uniform in nature.

If the electric field is zero, the electric potential is a constant value, but it does not tell you what that value is. All the electric field tells you is how the electric potential changes within the region you are looking at. If the electric potential at one end of a cylindrical region is 7 V and the electric field is zero within the whole cylinder, then the electric potential is 7 V at the other end, or somewhere in the middle, or on the side, and so forth. An electric field of zero tells you the potential does not change, but doesn't say anything about what it is outside of the region you're looking at.

The method of protecting a region from the effect of electric field is called electrostatic shielding. The electric field inside the cavity of a conductor is zero. Therefore, any instrument or an appliance can be placed in the cavity of a conductor so that it may not be affected by the electric field.