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Dear Wiki Questioner,

To calculate the kinetic energy of an object, we use the following equation:

KE=(1/2) m v^2

Where KE is the object's kinetic energy in Joules

m is the object's mass in kilograms

and v is the object's velocity in meters per second

So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation:

25g (1 kg/ 1000 g) = .025 kg

The mass of the bullet is .025 kilograms!

Now we plug the numbers into the equation and solve:

KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J

So the kinetic energy of your bullet is 3125 Joules

What else can I help you with?

Continue Learning about Physics

A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?

To determine the velocity of the bullet, we can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Given that the kinetic energy is 3150 joules and the mass is 60 grams (which is 0.06 kg), we can rearrange the formula to solve for v. Plugging in the values, we get 3150 = 0.5 * 0.06 * v^2. Solving for v, we find that the velocity of the bullet is approximately 250 meters per second.


What is the kinetic energy of a 8.47E plus 4 gram person moving at a velocity of 24.9 meters per second?

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At which temperature would the molecules in a one gram sample of water have at the lowest average kinetic energy?

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What will the kinetic energy be of an arrow after it is shot if it has a mass of 10 g and has a potential energy of 50 joules before it is shot?

If all of the potential energy is transferred to the arrow's motion as kinetic energy,then when the shot is complete and before any effect of air resistance has kicked in,its kinetic energy is 50 joules.KE = (mass) x (speed)250 = (.01) x V2V = sqrt(5000) = 70.711 meters per second, as it leaves the bow.Oops! Please excuse us. We thought you were going for the arrow's speed as it leftthe bow. Now we notice that you only wanted its kinetic energy. That's 50 joules,and it doesn't make any difference what its mass is. That was a 10-gram red herring.

Related Questions

What is kinetic energy of 124 grain 9mm bullet?

Conversions first. 124 grains (1 gram/15.43 grains)(1 kilogram/1000 grams) = 0.008036 kg ==============


A 60 gram bullet is fired from a gun with 3150 joule of kinetic energy what is its velocity?

To determine the velocity of the bullet, we can use the formula for kinetic energy: KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass, and v is the velocity. Given that the kinetic energy is 3150 joules and the mass is 60 grams (which is 0.06 kg), we can rearrange the formula to solve for v. Plugging in the values, we get 3150 = 0.5 * 0.06 * v^2. Solving for v, we find that the velocity of the bullet is approximately 250 meters per second.


What is The kinetic energy of a 25-gram bullet traveling at 500 ms?

Dear Wiki Questioner, To calculate the kinetic energy of an object, we use the following equation: KE=(1/2) m v^2 Where KE is the object's kinetic energy in Joules m is the object's mass in kilograms and v is the object's velocity in meters per second So for your question, we first convert the mass of the bullet into kilograms so we can use it in our equation: 25g (1 kg/ 1000 g) = .025 kg The mass of the bullet is .025 kilograms! Now we plug the numbers into the equation and solve: KE = (1/2) .025 kg (500 m/s)^2 = 3125 kg m^2/s^2 = 3125 J So the kinetic energy of your bullet is 3125 Joules


What is the kinetic energy of a 30 gram bullet that is traveling at 200 m s?

Kinetic energy = 0.5.m.v2 unit m = mass [=] kg v = velocity [=] m/s Gryazev-Shipunov GSh-30-2 firing 30 × 165mm bullet, bullet mass is 0.4 kg with velocity of 880 m/s Help your self press the calculator for the kinetic energy. Unit calculate is in Joules


Which has more kinetic energy the molecules in a gram of ice or a gram of steam?

The molecules in a gram of steam have more kinetic energy than the molecules in a gram of ice. This is because steam has a higher temperature and its molecules are moving faster compared to the slower-moving molecules in ice.


What is the kinetic energy of a 8.47E plus 4 gram person moving at a velocity of 24.9 meters per second?

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At which temperature would the molecules in a one gram sample of water have at the lowest average kinetic energy?

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What is energy transfer do gram for pendulum when it is released close to someone nose?

When a pendulum is released close to someone's nose, the energy transfer from the pendulum to the nose is mainly in the form of kinetic energy. As the pendulum swings down towards the nose, its potential energy is converted into kinetic energy, which can cause harm upon impact if not stopped. The amount of energy transferred will depend on the mass and velocity of the pendulum.


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KE = 1/2 M V2 = (0.5) x (0.0605) x (273)2 = 2,254.5 joules (rounded)That's considerable KE ! It's roughly the same as a 220-pound man moving at 15 mph.That helps me understand how a bullet can knock a big person down, not to mentiondoing some damage to his infrastructure..


What will the kinetic energy be of an arrow after it is shot if it has a mass of 10 g and has a potential energy of 50 joules before it is shot?

If all of the potential energy is transferred to the arrow's motion as kinetic energy,then when the shot is complete and before any effect of air resistance has kicked in,its kinetic energy is 50 joules.KE = (mass) x (speed)250 = (.01) x V2V = sqrt(5000) = 70.711 meters per second, as it leaves the bow.Oops! Please excuse us. We thought you were going for the arrow's speed as it leftthe bow. Now we notice that you only wanted its kinetic energy. That's 50 joules,and it doesn't make any difference what its mass is. That was a 10-gram red herring.


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