The idea here is to use Newton's Second Law, usually expressed as:F = ma (force = mass x acceleration)
Since both the acceleration and the mass are already in SI units, the force will be in newton.
The net force acting on the car is the difference between the applied force and the frictional force: ( F_{\text{net}} = F_{\text{applied}} - F_{\text{friction}} = 2250 N - 750 N = 1500 N ). To find the acceleration, we use the equation ( F_{\text{net}} = m \cdot a ), where m is the mass of the car (400 kg): ( a = F_{\text{net}} / m = 1500 N / 400 kg = 3.75 m/s^2 ). Therefore, a force of 2250 N will produce an acceleration of 3.75 m/s^2 on the car.
The acceleration of the car can be calculated using Newton's second law: a = F/m, where a is the acceleration, F is the net force, and m is the mass of the car. So, the acceleration of the car will be equal to the net force divided by the mass of the car in m/s^2.
The acceleration of the car can be calculated using the formula: acceleration = force / mass. Plugging in the given values: acceleration = 4000 N / 1000 kg = 4 m/s^2. Therefore, the car's acceleration when braking is 4 m/s^2.
The acceleration of a toy car on the floor will depend on various factors such as the force applied to it, the mass of the car, and the friction between the car and the floor. In general, the acceleration will be a result of the net force acting on the car divided by its mass, according to Newton's second law of motion (F=ma).
The acceleration of the car can be calculated using the formula: acceleration = net force / mass. Plugging in the values, acceleration = 1000N / 2000 kg = 0.5 m/s^2.
The net force acting on the car is the difference between the applied force and the frictional force: ( F_{\text{net}} = F_{\text{applied}} - F_{\text{friction}} = 2250 N - 750 N = 1500 N ). To find the acceleration, we use the equation ( F_{\text{net}} = m \cdot a ), where m is the mass of the car (400 kg): ( a = F_{\text{net}} / m = 1500 N / 400 kg = 3.75 m/s^2 ). Therefore, a force of 2250 N will produce an acceleration of 3.75 m/s^2 on the car.
The acceleration of the car can be calculated using Newton's second law: a = F/m, where a is the acceleration, F is the net force, and m is the mass of the car. So, the acceleration of the car will be equal to the net force divided by the mass of the car in m/s^2.
friction decreases the acceleration of a car by creating a greater force which pushes against the acceleration force. the friction is a force, but more of it means that whatever is pushing against it ( acceleration in this case) is made smaller.
well if both the car are identical in mass the acceleration is directly proportional to force and inversely proportional to mass since mass is same hence car having force of 1000 N will have more acceleration than 500 N one.
The acceleration of the car can be calculated using the formula: acceleration = force / mass. Plugging in the given values: acceleration = 4000 N / 1000 kg = 4 m/s^2. Therefore, the car's acceleration when braking is 4 m/s^2.
The acceleration of a toy car on the floor will depend on various factors such as the force applied to it, the mass of the car, and the friction between the car and the floor. In general, the acceleration will be a result of the net force acting on the car divided by its mass, according to Newton's second law of motion (F=ma).
The acceleration of the car can be calculated using the formula: acceleration = net force / mass. Plugging in the values, acceleration = 1000N / 2000 kg = 0.5 m/s^2.
The acceleration of the car can be calculated using the formula a = F/m, where a is acceleration, F is force, and m is mass. Plugging in the values, a = 4000N / 800 kg = 5 m/s^2. Therefore, the acceleration of the car is 5 m/s^2.
Increasing the force applied to a car will increase its acceleration, as described by Newton's second law (F=ma). However, there are other factors besides force that also affect acceleration, such as the car's weight, friction, and air resistance. It's important to consider overall driving conditions and safety when applying force to a car.
This scenario is possible if the car is moving in a circular path at constant speed. In circular motion, even though the speed is constant, the direction of the velocity is constantly changing, which requires a centripetal acceleration towards the center of the circle. This acceleration is provided by a net force, known as the centripetal force, acting towards the center of the circular path.
The acceleration of the car can be calculated using the formula F=ma, where F is the force applied (600 N) and m is the mass of the car (1200 kg). Rearranging the formula to solve for acceleration gives a = F/m. Therefore, the acceleration of the car is 0.5 m/s^2.
Impulse = Force x timeImpulse = 500 x 0.5Impulse = 250 Ns