The equivalent weight of NaHCO3 (sodium bicarbonate) is calculated by dividing the molar mass by the number of replaceable hydrogen ions (equivalents) in the compound. The molar mass of NaHCO3 is approximately 84 grams per mole. Since NaHCO3 has one replaceable hydrogen ion, its equivalent weight is also 84 grams per equivalent. This value is used in stoichiometry calculations to determine the amount of a substance needed to react with a given number of equivalents of another substance.
equivalent weight of succinic acid is 118/2 is 59
105kg is equivalent to 231.5 pounds in weight.
77 kilos IS weight
Weight that is 6.5kg is equivalent to 14.3 lbs. Weight that is 8kg is equivalent to 17.6 lbs.
28g is equivalent to 0.028 kilograms in weight.
To convert mEq to mg for NaHCO3, you need to multiply the mEq value by the molecular weight of NaHCO3. The molecular weight of NaHCO3 is 84 g/mol. Therefore, you would multiply 200 mEq by 84 to get the equivalent amount in mg, which is 16800 mg.
The gram-equivalent weight of sodium bicarbonate is calculated by dividing the molar mass by the number of equivalents of the compound. For sodium bicarbonate (NaHCO3), the molar mass is approximately 84 grams per mole. Since it has one equivalent of bicarbonate ion (HCO3^-), the gram-equivalent weight of sodium bicarbonate is 84 grams.
The answer is NaHCO3
Sodium Bicarbonate come from absorption of CO2 into NaOH Total reaction is 2NaOH + CO2 -> NaHCO3 + H2O Each mole of NaHCO3 come from absorption of 1 mole CO2 Molecular weight of NaHCO3 is 84 g/mol and CO2 is 44 g/mol It is that 84 g of NaHCO3 had 44 g of CO2 By weight ratio it is 52% CO2 in Sodium Bicarbonate.
The common name for sodium hydrogen carbonate (NaHCO3) is baking soda.
Divide 6.10 (g NaHCO3) by 84.007 (g.mol−1 NaHCO3) to get 0.0726 mol NaHCO3
The ratio of NaHCO3 to WHAT!
Several part problem. Get molarity of NaHCO3. (150 ml)( M NaHCO3) = (150 ml)(0.44 M HCl) = 0.44 M NaHCO3 --------------------------- get moles NaHCO3 ( 150 ml = 0.150 Liters ) 0.44 M NaHCO3 = moles NaHCO3/0.150 Liters = 0.066 moles NaHCO3 ---------------------------------------get grams 0.066 moles NaHCO3 (84.008 grams/1 mole NaHCO3) = 5.54 grams NaHCO3 needed ---------------------------------------------answer
NaHCO3 is commonly called bicarbonate of soda or baking soda.
For this you need the atomic (molecular) mass of NaHCO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaHCO3=84.0 grams110 grams NaHCO3 / (84.0 grams) = 1.31 moles NaHCO3
the equivalent weight of chlorine is 35.453, which is also it's atomic weight.
The chemical formula for sodium bicarbonate is NaHCO3.