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Explains why a balloon bulges on one end when you pinch the other end?

The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.


How does a balloon pump work?

A balloon pump works by pushing air into the balloon through a narrow nozzle. By squeezing the handle, the pump creates pressure that forces air to flow into the balloon, inflating it. The one-way valve on the pump prevents air from escaping and maintains the balloon's inflation.


Why does an increase in temperature increase the volume of a balloon?

This requires one simple equation and then a further understanding of it. PV=nRT where P is pressure, V is volume, T is temperature, n is the number of molecule, R is some constant. From this we can easily see that an increase in temperature does in fact cause an increase in volume. To see why lets think about what temperature is. Temperature is a measure of average kinetic energy. So an increase in temperature increases the average kinetic energy. An increase in average kinetic energy means that average velocity must be increased (K.E = .5(mv^2)). More velocity means that the molecules in the balloon are flying faster, and since pressure is the same, the molecules spread out more, which must increase the volume.


If you push on the sides of a filled balloon how does the pressure inside change?

If the balloon is not encased or in restricted volume, then it changes its shape to accomodate that push but prutruding on the other side and the pressure remain same. However, if there is restriction for shape change, then when you push on the balloon, the volume decreases and therefore the pressure increases. A practical balloon, by the way, will behave between these two extremes. Pushing on one side and causing it to change shape definitely results in an increase in internal pressure. This is because the elasticity/tension of the rubber is the encased space.


What makes a balloon go forward when the air is released?

The air inside the balloon is at a higher pressure than atmospheric pressure so the gas molecules inside the balloon are closer together on average than gas molecules outside the balloon. This means that the repulsive forces between the gas molecules inside the balloon are greater than the repulsive forces between the gas molecules outside it. When the balloon is opened, the gas molecules in the open end at the border between the higher pressure interior and lower pressure exterior will experience a greater repulsive force from the gas molecules inside the balloon than the molecules on the outside. This means that they experience a net force pushing them out of the balloon. As these gas molecules are pushed out by the gas inside the balloon, they push back on it with an equal and opposite force (due to Newton's 3rd Law of Motion). This equal and opposite reaction force causes the gas in the balloon to be pushed in the opposite direction to the escaping gas, which in turn pushes the balloon. As more and more gas escapes, the reaction force on the balloon continues to accelerate it, making it shoot off, until enough gas has escaped for the pressure inside the balloon to have dropped to the same level as the pressure outside the balloon.

Related Questions

Explains why a balloon bulges on one end when you pinch the other end?

The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.


What explains why a balloon bulges on one end when you pinch the other end?

The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.


How does a balloon pump work?

A balloon pump works by pushing air into the balloon through a narrow nozzle. By squeezing the handle, the pump creates pressure that forces air to flow into the balloon, inflating it. The one-way valve on the pump prevents air from escaping and maintains the balloon's inflation.


Why does an increase in temperature increase the volume of a balloon?

This requires one simple equation and then a further understanding of it. PV=nRT where P is pressure, V is volume, T is temperature, n is the number of molecule, R is some constant. From this we can easily see that an increase in temperature does in fact cause an increase in volume. To see why lets think about what temperature is. Temperature is a measure of average kinetic energy. So an increase in temperature increases the average kinetic energy. An increase in average kinetic energy means that average velocity must be increased (K.E = .5(mv^2)). More velocity means that the molecules in the balloon are flying faster, and since pressure is the same, the molecules spread out more, which must increase the volume.


What is the Proof in daily life of air exerting pressure?

If you evacuate all the air between 2 pieces of glass, the glass is pressed together by atmospheric pressure from the outside. By measuring the force needed to separate the panes of glass, one can extrapolate the pressure exerted on the glass.


If you push on the sides of a filled balloon how does the pressure inside change?

If the balloon is not encased or in restricted volume, then it changes its shape to accomodate that push but prutruding on the other side and the pressure remain same. However, if there is restriction for shape change, then when you push on the balloon, the volume decreases and therefore the pressure increases. A practical balloon, by the way, will behave between these two extremes. Pushing on one side and causing it to change shape definitely results in an increase in internal pressure. This is because the elasticity/tension of the rubber is the encased space.


Which one of the following situations would cause air pressure to rise an increase in temperature cold air entering the region moisture entering the air?

An increase in temperature would cause air pressure to rise. As air warms, its molecules gain more kinetic energy and spread further apart, leading to an increase in pressure. Cold air entering a region or moisture entering the air would not directly cause air pressure to rise.


What makes a balloon go forward when the air is released?

The air inside the balloon is at a higher pressure than atmospheric pressure so the gas molecules inside the balloon are closer together on average than gas molecules outside the balloon. This means that the repulsive forces between the gas molecules inside the balloon are greater than the repulsive forces between the gas molecules outside it. When the balloon is opened, the gas molecules in the open end at the border between the higher pressure interior and lower pressure exterior will experience a greater repulsive force from the gas molecules inside the balloon than the molecules on the outside. This means that they experience a net force pushing them out of the balloon. As these gas molecules are pushed out by the gas inside the balloon, they push back on it with an equal and opposite force (due to Newton's 3rd Law of Motion). This equal and opposite reaction force causes the gas in the balloon to be pushed in the opposite direction to the escaping gas, which in turn pushes the balloon. As more and more gas escapes, the reaction force on the balloon continues to accelerate it, making it shoot off, until enough gas has escaped for the pressure inside the balloon to have dropped to the same level as the pressure outside the balloon.


What change in pressure occurs in a party balloon that is squeezed to one-third its volume with no change in temperature?

The pressure of the balloon increases threefold when it is squeezed to one-third its volume with no change in temperature. This is because pressure is inversely proportional to volume according to Boyle's Law, which states that when volume decreases, pressure increases.


Why does a balloon pop when it stepped on?

It depends upon the strength of the rubber making up the balloon and how much air is already in it, which will increase pressure in certain regions of balloon when stepped on. The assumption is the one is stepping on the balloon with a wide shoe bottom, rather than a stiletto heel. Sometimes, you can step on a balloon, and the part under the foot gets flattened as the air gets displaced into the stretching parts of the balloon coming out from under the sides of the foot. If the air content is low enough to not overcome the tensile strength of the rubber, then the balloon will not pop. However, if there is enough air in the balloon to overcome the tensile strength of the rubber as the air pressure increases when you step on the balloon, then the balloon will pop. What happens is the part of the balloon under the foot remains still, and the air is forced away from that region, placing more air pressure on the rest of the balloon. This stretches the balloon so that it comes out the sides of the foot. In these regions, the air pressure is much greater. Now, due to the special intermolecular bonds in rubber, the molecules can remain bound but still stretch and bend, allowing for rubber to stretch. As air pressure builds, it produces a force against the inside of the rubber, causing the rubber to stretch. If the rubber stretches past the point where the molecules separate enough to form a small tear (air hole) in the rubber, then the overall forces placed on the rubber cause a VERY rapid failure in the adjacent regions of the rubber to maintain integrity. They rip, and the rubber next to it rips, and so forth in what is called cascade failure. In all, a large rip forms along the rubber as the air escapes its container (the balloon).


Why does a balloon pop when stepped on?

It depends upon the strength of the rubber making up the balloon and how much air is already in it, which will increase pressure in certain regions of balloon when stepped on. The assumption is the one is stepping on the balloon with a wide shoe bottom, rather than a stiletto heel. Sometimes, you can step on a balloon, and the part under the foot gets flattened as the air gets displaced into the stretching parts of the balloon coming out from under the sides of the foot. If the air content is low enough to not overcome the tensile strength of the rubber, then the balloon will not pop. However, if there is enough air in the balloon to overcome the tensile strength of the rubber as the air pressure increases when you step on the balloon, then the balloon will pop. What happens is the part of the balloon under the foot remains still, and the air is forced away from that region, placing more air pressure on the rest of the balloon. This stretches the balloon so that it comes out the sides of the foot. In these regions, the air pressure is much greater. Now, due to the special intermolecular bonds in rubber, the molecules can remain bound but still stretch and bend, allowing for rubber to stretch. As air pressure builds, it produces a force against the inside of the rubber, causing the rubber to stretch. If the rubber stretches past the point where the molecules separate enough to form a small tear (air hole) in the rubber, then the overall forces placed on the rubber cause a VERY rapid failure in the adjacent regions of the rubber to maintain integrity. They rip, and the rubber next to it rips, and so forth in what is called cascade failure. In all, a large rip forms along the rubber as the air escapes its container (the balloon).


What is the physical change of the Two balloons one inflated and the other deflated?

The inflated balloon has air inside it, causing it to expand and increase in size. The deflated balloon has no air inside it, so it appears shriveled or smaller in size.