This requires one simple equation and then a further understanding of it.
PV=nRT where P is pressure, V is volume, T is temperature, n is the number of molecule, R is some constant.
From this we can easily see that an increase in temperature does in fact cause an increase in volume. To see why lets think about what temperature is.
Temperature is a measure of average kinetic energy. So an increase in temperature increases the average kinetic energy. An increase in average kinetic energy means that average velocity must be increased (K.E = .5(mv^2)). More velocity means that the molecules in the balloon are flying faster, and since pressure is the same, the molecules spread out more, which must increase the volume.
The pressure inside the balloon will increase due to the increase in temperature caused by the rubbing (which is a form of mechanical work). According to the ideal gas law, pressure is directly proportional to temperature when volume is constant.
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v
The air pressure inside the balloon will increase when it is squeezed to half its volume at constant temperature. This is because the volume of the balloon decreases, leading to the air molecules being more confined in a smaller space, resulting in higher pressure.
If a balloon is heated, the temperature inside the balloon increases, causing the air molecules to move faster and collide more frequently with the walls of the balloon. This increase in collisions leads to an increase in pressure inside the balloon, assuming the volume remains constant according to the ideal gas law (P1/T1 = P2/T2).
Charles' Law states that as temperature of a gas increases, its volume also increases if pressure remains constant. When a balloon is heated, the air inside it warms up and expands, causing the volume of the gas to increase. This increase in volume causes the balloon to rise because it becomes less dense than the surrounding air.
The volume will increase in proportion to the increase in absolute temperature.
The volume will increase in proportion to the increase in absolute temperature.
The volume of the balloon will increase on the sunny windowsill due to the increase in temperature. This follows Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is constant.
It would increase. The balloon would expand because when temperature increases, volume increases as well.
The pressure inside the balloon will increase due to the increase in temperature caused by the rubbing (which is a form of mechanical work). According to the ideal gas law, pressure is directly proportional to temperature when volume is constant.
The kinetic energy of the particles inside the balloon increase. This then expands the volume of the balloon.
It would increase in volume. According to Charles' Law, as you increase temperature the volume will increase as well. So if you would put it in a freezer, it would shrink because as you decrease temperature, you decrease volume.
Decrease the pressure of the surrounding environment. Thus, the force acting on the balloon from the outside decreases, allowing the air pressure that creates a force inside the balloon to have less of a counteracting force.
The volume of the weather balloon would increase. This is because as the temperature of a gas increases, the molecules move faster and spread out more, leading to an increase in volume according to Charles's Law.
When the temperature is colder the particles in the balloon travel slower, making the balloon not able to increase in size it decreases.When the temperature is hot it allows the balloon to expand because the particles in the balloon are moving rapidly. in conclusion the the cold makes the balloon decrease in size and the heat allows it to expand.
If the pressure is kept constant while increasing the temperature of the air in a balloon, the volume of the gas inside the balloon would change. This is because as the temperature rises, the gas molecules gain energy and move faster, leading to an increase in volume to maintain a constant pressure.
Nothing happens to the mass of the balloon. Mass is conserved, so the temperature of the balloon will not affect it's mass. Mass can be thought of the amount of "stuff" that makes up a balloon. It can be obtained by adding up the mass of all the molecules of rubber in the balloon. Obviously, putting the balloon in a warm room will not change the number of molecules in the balloon, therefore the mass stays constant. The volume of the balloon will probably increase. Because volume increases but mass remains constant, the density of the balloon would decrease. D = m/v