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You are not providing sufficient information for an answer. Is this object initially stationary? Is it falling to Earth? If so, it is accelerated at a rate of 32 feet per second per second (ignoring air resistance, which will actually make a huge difference). The question then becomes: When? Are you asking what its speed will be upon impact? With air resistance, something called "terminal velocity" comes into play: http://en.wikipedia.org/wiki/Terminal_velocity
What else can I help you with?
How fast is an object travelling at point of impact after falling sixteen feet?
The speed of an object falling freely without air resistance from a height of 16 feet can be calculated using the equation V = √(2gh), where V is the final velocity, g is the acceleration due to gravity (32 ft/s^2), and h is the height. Plugging in the values, the speed of the object at impact would be approximately 28 feet per second.
What is the net force of a 7 pound object falling 20 inches?
The net force acting on the object can be calculated using the equation F = m*a, where F is the force, m is the mass of the object, and a is the acceleration due to gravity. The mass of the object can be converted from pounds to slugs, and the acceleration due to gravity is approximately 32 ft/s^2. Plugging in the values, we can calculate the net force.
What is the numerical ratio of a velocity to speed of an object?
Velocity is an object's Speed + Direction. For example, a cannon ball fired up at 45o to the ground may have a speed of 1000 ft/sec. However, its forward Velocity is:(1000 ft/sec) x (Sine 45o) = (1000 ft/sec) x (.707)= 707 ft/secSo, the ratio of the horizontal Velocity to the instantaneous Speed of the object is the SINE value of the angle of motion relative to the Horizontal axis.But you have to remember that there is a Vertical component of the object's Speed as well. In this case, the ratio is the COSINE 45o , which happens to be .707 as well. So the ball is going forward at 707 ft/sec, and upward at 707 ft/sec. at the same time.
What is the velocity of a 4.5 Pound object falling thirty feet?
Ignoring air resistance ... Any object dropped near the Earth's surface reaches a speed of 43.9 feet per second after falling 30 feet. The velocity is 43.9 feet per second down. The object's weight makes no difference.
Does the speed of falling objects increase at a constant rate?
The speed of an object falling towards the earth will increase because the gravitational force on the object will accelerate it at a rate of 9.8 m/s² (32.2 ft/sec2). So the speed of a falling body can be calculated by the simple formula: v=u+at Where v = current vertical speed u = vertical speed when it began to fall a = acceleration t = time since it began to fall All of this describes how gravity works. If an object doesn't behave according to this description, the reason is that it's falling through air, which tries to slow it down. (Think of a parachute.) Where there is no air, falling objects behave exactly this way. Notice that the mass or weight of the object doesn't appear anywhere in the math. Where there is no air, all objects, no matter what they weigh, including feathers, rocks, airplanes, sheets of paper, and parachutes, fall with the same acceleration, and every object that falls from the same height hits the ground at the same speed.
Integer for 28000 ft above sea level?
+28000 FT
How fast is an object travelling at point of impact after falling sixteen feet?
The speed of an object falling freely without air resistance from a height of 16 feet can be calculated using the equation V = √(2gh), where V is the final velocity, g is the acceleration due to gravity (32 ft/s^2), and h is the height. Plugging in the values, the speed of the object at impact would be approximately 28 feet per second.
How do you convert 28000 square feet into square meters?
Answer: 1 ft² = 0.092903 m² so, 28000 x 0.092903 = 2601.285 m²
What is the net force of a 7 pound object falling 20 inches?
The net force acting on the object can be calculated using the equation F = m*a, where F is the force, m is the mass of the object, and a is the acceleration due to gravity. The mass of the object can be converted from pounds to slugs, and the acceleration due to gravity is approximately 32 ft/s^2. Plugging in the values, we can calculate the net force.
The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 91 ft in 2 seconds how far will it have fallen?
The answer is 91 ft, of course!
How do you calcalate the speed of an object?
Distance divided by time.For example..( 300 ft. x 3600 seconds ( 1 hour ) = 1,080,000 ft. / 5280 ft. ( 1 mile ) = 204.5455 mph )An object travels 300 ft in 1 second, the object is travelling at 204.5455 Mph.
What is the numerical ratio of a velocity to speed of an object?
Velocity is an object's Speed + Direction. For example, a cannon ball fired up at 45o to the ground may have a speed of 1000 ft/sec. However, its forward Velocity is:(1000 ft/sec) x (Sine 45o) = (1000 ft/sec) x (.707)= 707 ft/secSo, the ratio of the horizontal Velocity to the instantaneous Speed of the object is the SINE value of the angle of motion relative to the Horizontal axis.But you have to remember that there is a Vertical component of the object's Speed as well. In this case, the ratio is the COSINE 45o , which happens to be .707 as well. So the ball is going forward at 707 ft/sec, and upward at 707 ft/sec. at the same time.
How many cubic feet in 28000 gal?
28,000 US gallons equates to 3,743.1 cubic feet.
What is the velocity of a 4.5 Pound object falling thirty feet?
Ignoring air resistance ... Any object dropped near the Earth's surface reaches a speed of 43.9 feet per second after falling 30 feet. The velocity is 43.9 feet per second down. The object's weight makes no difference.
Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 3 seconds ago is falling?
The rule for calculating the velocity of a falling object is V = gt, where V is velocity, g is the acceleration due to gravity (32 ft/s^2), and t is time. For an object dropped 3 seconds ago, the velocity would be V = 32 ft/s^2 * 3 s = 96 ft/s.
Does the speed of a solid increase while falling under the action of gravity?
yes 9.81 m/s2 or 32.2 ft/s2
Does the speed of falling objects increase at a constant rate?
The speed of an object falling towards the earth will increase because the gravitational force on the object will accelerate it at a rate of 9.8 m/s² (32.2 ft/sec2). So the speed of a falling body can be calculated by the simple formula: v=u+at Where v = current vertical speed u = vertical speed when it began to fall a = acceleration t = time since it began to fall All of this describes how gravity works. If an object doesn't behave according to this description, the reason is that it's falling through air, which tries to slow it down. (Think of a parachute.) Where there is no air, falling objects behave exactly this way. Notice that the mass or weight of the object doesn't appear anywhere in the math. Where there is no air, all objects, no matter what they weigh, including feathers, rocks, airplanes, sheets of paper, and parachutes, fall with the same acceleration, and every object that falls from the same height hits the ground at the same speed.
