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What is the acceleration due to gravity at distance of 2 earth radii above earth's surface?
Wiki User
∙ 13y ago
The force of gravity between two masses is inversely proportional to the square of the distance
between them.
So when you move from (1 earth radius away from the center) out to (10 of them), the force between
you and the earth becomes
1/102 = 1/100 = 1 percent
of what it was originally.
Notice that gravity doesn't "become weaker" out there. It still follows exactly the same physical laws.
And in precise accordance with those laws, the mutual gravitational force between you and the earth
becomes 99% less than it is at the earth's surface.
Wiki User
∙ 14y ago
Wiki User
∙ 13y agoThe distance from the earth's center of mass at 2 radii is 3 times the value
at the surface.
Since the acceleration (and force) of gravity vary as 1/R2 , they decrease to
1/9th of the surface value at 2 radii off the surface.
[ 9.8 meters (32.2 feet) per second2 ] / 9 = 1.09 meter (3.57 ft) per second2
(This is all ignoring any effects of being closer to the moon, which we haven't
even bothered to look at and decide whether or not it's significant. In any case,
the calc above refers exclusively to the acceleration of gravity due to the earth's
presence.)
Wiki User
∙ 8y ago
The acceleration of gravity is inversely proportional to the square of the
distance from the mass.
At 3 Earth radii above the surface, your distance from the Earth's center is
3 times the distance on the surface, and the acceleration of gravity is
1/(3^2) = 1/9
of its value on the surface.
The surface value is 9.807 m/s^2 (rounded). So at 3 Earth radii up
(about 12,000 miles), it's
(9.807/9) = 1.09 m/s^2 (rounded) .
david.mckinley
The acceleration of gravity is inversely proportional to the square of the distance from the mass.
At 3 Earth radii above the surface, your distance from the Earth's center is 4 times the distance on the surface (the surface is one Earth radius from the center, so if you are 3 radii above the surface you are a total of 3+1=4 radii from the center).
Thus, the acceleration of gravity is1/(4^2) = 1/16 of its value on the surface.
The surface value is 9.807 m/s^2 (rounded). So at 3 Earth radii up(about 12,000 miles), it's(9.807/16) = 0.61 m/s^2 (rounded) .
Wiki User
∙ 15y agoEarth doesn't pull us down, but space pushes us into the earth.
Wiki User
∙ 12y agoa = 9.82 / ((2 / 1)^2) = 9.82 / 4 = 2.455 ((m/s)/s)
Wiki User
∙ 11y ago1
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Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
When you push UP on an object when object is stationary on earths surface you increase your weight when you push DOWN on an object when object is stationary on earths surface you decrease your weight?
No, your weight is just the acceleration due to the Earth's gravity,
What is the importance of 9.81 in accelaration due to gravity?
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
What is the acceleration due to gravity near the earth's surface?
9.81 m/s2 gravity is dependant on the total mass of the two bodies, and the distance between their mass centers, and irrespective of any motion or rotation on earth, their would be a very small acceleration due to rotation about the earths axis (0 at the poles , maximum at the equator) , but this is a totally seperate issue
Where does gravity pull people and objects?
On the earths surface gravity pulls you down.
What is makemakes gravity compared to earths gravity?
The acceleration of gravity at its surface is currently estimated as 0.4 m/s2 .That's about 4% of the acceleration of gravity on the Earth's surface.
Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?
Because the acceleration of gravity on the surface of any given body depends on the mass of the body and its radius ... the distance of the surface from the center. Mars' mass ... about 11% of Earth's ... and Mars' radius ... about 53% of Earth's ... combine to produce about 38% of Earth's gravitational acceleration at the surface of Mars.
Why is acceleration due to gravity the same for all objets?
because all are measured at the same radius from the earths cog, if you doubled this distance, the acceleration would be only one quarter that of the surface
Where do you experience more gravity on earths surface or earths center?
on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.
What is the surface gravity on earth?
The force of gravity on the earth is 9.8 m/s^2
What is the affect of rotation of the earth on acceleration due to gravity?
Gravity is pretty constant figure anywhere on earth, essentially its dependent on your distance from the center of gravity of the earth, nominally it will produce an acceleration of 9.81((m/s/)/s) at the earths surface. Gravity is dependent on mass and independent of motion , ie mass of earth attracting mass of person , attraction being proportional to total mass of both and distance between their centers of gravity. However , a very small opposing acceleration outwards is experienced because you are rotating about the earths axis (centrifugal action) , its maximum effect is on the equator and zero effect at the poles. this acceleration can be calculated from: a = (v^2)/r where: a = acceleration ((m/s)/s) v = velocity (m/s) r = radius or normal distance from earths axis (m)
What is the compare of the earth and the moon in terms of size and surface gravity?
earth is 81.3 times the mass of the moon . acceleration due to gravity at earths surface = 9.82 (m/s)/s acceleration due to gravity at moons surface = 1.62 (m/s)/s . 1 kg at earths surface, force = 1 * 9.82 = 9.82 newtons 1 kg at moons surface, force = 1 * 1.62 = 1.62 newtons
When you push UP on an object when object is stationary on earths surface you increase your weight when you push DOWN on an object when object is stationary on earths surface you decrease your weight?
No, your weight is just the acceleration due to the Earth's gravity,
What is the importance of 9.81 in accelaration due to gravity?
9.81 is the acceleration due to the force of gravity experienced by bodies on or about the surface of the earth (nominally at sea level) the units are meters per second / per second, that is to say a stone dropped from a height will gain 9.81 m/s velocity for every second it falls (is in freefall) however , if you move from the earths surface , this figure will diminish, an example being : if you double your distance from the earths centre you will experience 1/4 of the acceleration (or force) you experienced at the surface
When drawing the graph of distance vs time squared how do you calculate the the acceleration due to gravity?
Example: x axis = time, y axis = distance, plot values of s, when t = say 0 to 10, step 1 > If time is the variable, and distance the dependent, you should have been given a figure for acceleration (g), without which, you cant plot the graph. > Acceleration due to earths gravity (g) at earths surface radius is generally taken as = 9.82 metres per second / per second. > Use: s = (u*t) + (0.5 * g * t2) > where: s = distance u = initial velocity g = acceleration due to gravity (9.82 (m/s)/s) t = elapsed time
Why does the acceleration of gravity vary from one point to another on the earths surface?
Different air pressure, so there is more/less air resistance.
Which force acts from a distance to play a role both in the formation of tides and mass movements on earths surface?
Gravity.
