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Why there is no acceleration along x axis during projectile motion?
There is no force that acts upon the object in that direction. Gravity only acts on the y axis. Though there is some wind resistance that does cause a negative acceleration in the x direction. You are probably just being told to ignore this as it is usually negligible.
True or false near the earth surface the amount of mass an object has does not affect its acceleration due to gravity?
True. Near the Earth's surface, the acceleration due to gravity is constant at approximately 9.81 m/s^2 regardless of the mass of the object. This principle was famously demonstrated by Galileo when he dropped objects of different masses from the Leaning Tower of Pisa.
A ball is thrown vertically plus How long does it take to reach its highest point?
The answer depends on what information you have and also what factors youu are taking into account. If you are given the initial velocity, U m/s, and ignore aeronautic drag, then the time, t, is given byt = u/g where g = the acceleration due to gravity = 9.81 ms^-2 (approx).
3 A tank with a flat bottom is filled with water to a height of 4 meters What is the pressure at any point at the bottom of the tank You can ignore atmospheric pressure when calculating your?
Since we are ignoring atmospheric pressure, the pressure at the bottom of the tank is given by p = dgh. Where d equals density, g is acceleration of gravity, and h is the height below the fluid surface. In this case, the density of water is 10^3 kg/m^3, the acceleration of gravity is 9.8 m/s^2, and the height is 4 m. This means the pressure is 39.2 kPa.
Below is the rule for calculating the velocity of a falling object?
If you can ignore the effects of air resistance, then . . .The speed of a falling object isS = s0 + G TS = speed at any time after it's droppeds0 =initial speed you gave it when you dropped it; if you just openedyour hand and let it roll out, then s0 is zero.G =acceleration of gravity; On Earth: 9.8 meters (32.2 feet) per second2T =length of time it has been falling.That's the speed of the falling object, also the magnitude of its velocity.The direction of velocity is on a line toward the center of the Earth, typicallyreferred to in most places as "down".
Why there is no acceleration along x axis during projectile motion?
There is no force that acts upon the object in that direction. Gravity only acts on the y axis. Though there is some wind resistance that does cause a negative acceleration in the x direction. You are probably just being told to ignore this as it is usually negligible.
True or false near the earth surface the amount of mass an object has does not affect its acceleration due to gravity?
True. Near the Earth's surface, the acceleration due to gravity is constant at approximately 9.81 m/s^2 regardless of the mass of the object. This principle was famously demonstrated by Galileo when he dropped objects of different masses from the Leaning Tower of Pisa.
What is the formula to find the mass when they give you the acceleration and mass?
You ignore the acceleration, and just give them the mass. Now, if they give you the acceleration and the applied force, you could use m = F/a.
Ignoring air resistance a rock in free fall will have a velocity of what after 4 seconds?
The final velocity is simply acceleration x time. The distance can be calculated from: d = 1/2 acceleration time squared + (initial speed) x time Since the initial speed is assume to be zero, you can simply ignore the second term. The acceleration due to gravity is approximately 9.8 meters per second squared.
A ball is thrown vertically plus How long does it take to reach its highest point?
The answer depends on what information you have and also what factors youu are taking into account. If you are given the initial velocity, U m/s, and ignore aeronautic drag, then the time, t, is given byt = u/g where g = the acceleration due to gravity = 9.81 ms^-2 (approx).
A ball is thrown vertically upward. What are its velocity and acceleration when it reaches its maximum altitude What is the acceleration of the ball just before it hits the ground?
At the maximum height the ball will be completely stopped from moving upward or downward; thus the speed of the ball would be 0 mph. The ball is only stopped for a split second and then it begins moving downward, then increasing at 9.81m/s^2 until it reaches maximum velocity.
How does acceleration due to gravity of the large ball compare to the smaller ball?
If you let two balls fall, initially the velocity will be the same. A small (and light) objects will eventually fall slower, because of increased air resistance. But if you can ignore air resistance - distances are short, or you do the experiment in a vacuum - acceleration will continue to be the same - on Earth, about 9.8 (meters per second) per second.If you let two balls fall, initially the velocity will be the same. A small (and light) objects will eventually fall slower, because of increased air resistance. But if you can ignore air resistance - distances are short, or you do the experiment in a vacuum - acceleration will continue to be the same - on Earth, about 9.8 (meters per second) per second.If you let two balls fall, initially the velocity will be the same. A small (and light) objects will eventually fall slower, because of increased air resistance. But if you can ignore air resistance - distances are short, or you do the experiment in a vacuum - acceleration will continue to be the same - on Earth, about 9.8 (meters per second) per second.If you let two balls fall, initially the velocity will be the same. A small (and light) objects will eventually fall slower, because of increased air resistance. But if you can ignore air resistance - distances are short, or you do the experiment in a vacuum - acceleration will continue to be the same - on Earth, about 9.8 (meters per second) per second.
3 A tank with a flat bottom is filled with water to a height of 4 meters What is the pressure at any point at the bottom of the tank You can ignore atmospheric pressure when calculating your?
Since we are ignoring atmospheric pressure, the pressure at the bottom of the tank is given by p = dgh. Where d equals density, g is acceleration of gravity, and h is the height below the fluid surface. In this case, the density of water is 10^3 kg/m^3, the acceleration of gravity is 9.8 m/s^2, and the height is 4 m. This means the pressure is 39.2 kPa.
At what part of the trajectory does a projectile have maximum speed?
The maximum speed of a fired projectile, unless fired downward in a vacuum, is the muzzle velocity - this is when the propulsive acceleration ceases. Ignoring air resistance, the projectile would maintain its horizontal velocity, while gravity would first reduce then restore the vertical component. Terminal velocity, the maximum possible atmospheric speed, is determined by mass, gravity, air density, and projectile shape, as gravitic acceleration is slowed by air resistance.
Below is the rule for calculating the velocity of a falling object?
If you can ignore the effects of air resistance, then . . .The speed of a falling object isS = s0 + G TS = speed at any time after it's droppeds0 =initial speed you gave it when you dropped it; if you just openedyour hand and let it roll out, then s0 is zero.G =acceleration of gravity; On Earth: 9.8 meters (32.2 feet) per second2T =length of time it has been falling.That's the speed of the falling object, also the magnitude of its velocity.The direction of velocity is on a line toward the center of the Earth, typicallyreferred to in most places as "down".
If a cliff is 50meters high ignore air resistance how long to hit bottom?
Time to hit bottom of a cliffIf you ignore the air resistance, any falling body will accelerate at the same constant rate under the action of gravity. On the earth, the accelaration of the gravity is about 9.81 m/s2 (9.81 meter per second squared). This is to say that the speed of the falling body will increase by 9.81 m/s, every second.For a body accelerating from rest, the distance travelled and the time elapsed are related by the equation:D = (a*t2)/2where 'D' is the distance, 'a' the acceleration and 't' the time. Furthermore, the velocity 'V' of the body after 't' seconds under the same acceleration will be:V = a*tUsing these two relations, one can easily determine that a body falling from the top of a cliff 50 meters high will hit the bottom in about 3.19 seconds, at a speed of approximately 31.3 m/s (which is about 112,8 km/h or 67.7 mph).
If an object is released from rest and falls for 5 seconds How far did the object fall?
For this we calculation must consider the equations=uv + 1/2 at2Where s = displacement, u= initial velocity, v= velocity, a= acceleration & t=time.Since initial velocity is is at rest hence 0 we can ignore the uv.Also the acceleration is gravity or g.So therefores=1/2 gt2For earth g= 9.812865328 m/sand t= 5 ssos= 1/2*9.812865328*(5)2s= 122.66mThis answer of course does not take into consideration wind resistance.
