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What is the acceleration of a 40-kg pail of cement when pulled sideways with a net force of 200 N?
The acceleration of the pail of cement can be calculated using Newton's second law: F = ma, where F is the net force, m is the mass, and a is the acceleration. Plugging in the values, we get a = F/m = 200 N / 40 kg = 5 m/s^2. Therefore, the pail of cement will accelerate sideways at 5 m/s^2.
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What is the acceleration of a 40-kg block of cement when pulled sideways with the net force of 200 N?
The acceleration of the block of cement can be calculated using Newton's second law: a = F/m, where F is the net force and m is the mass of the block. Plugging in the values, we get a = 200 N / 40 kg = 5 m/s^2. Therefore, the acceleration of the block of cement is 5 m/s^2.
A 50kg block of cement is pulled upward with a force of 600NWhat is its acceleration?
Using Newton's second law (F=ma), the acceleration can be calculated by dividing the force applied by the mass of the block. Therefore, the acceleration of the 50kg block under a 600N force is 600N / 50kg = 12 m/s^2.
What is the acceleration of a 7 kg mass being pulled by a 56 newton force?
The acceleration of the 7 kg mass being pulled by a 56 N force can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma). Rearranging the formula, acceleration (a) = force (F) / mass (m). Plugging in the values, we get acceleration = 56 N / 7 kg = 8 m/s^2.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
A block has acceleration A when pulled by a string If two identical blocks are glued together and pulled with twice the original force what will their acceleration be?
I think so. I'm not a physics expert but see if this makes sense to you.Force = mass * accelerationdouble the mass and you getForce = 2 * mass * accelerationdouble the force with double the mass and you get2 * Force = 2 * mass * accelerationusing simple division math you cancel the 2's which results inForce = mass * accelerationSo I think it would be the same acceleration.
What is the acceleration of a 40-kg block of cement when pulled sideways with the net force of 200 N?
The acceleration of the block of cement can be calculated using Newton's second law: a = F/m, where F is the net force and m is the mass of the block. Plugging in the values, we get a = 200 N / 40 kg = 5 m/s^2. Therefore, the acceleration of the block of cement is 5 m/s^2.
A 50kg block of cement is pulled upward with a force of 600NWhat is its acceleration?
Using Newton's second law (F=ma), the acceleration can be calculated by dividing the force applied by the mass of the block. Therefore, the acceleration of the 50kg block under a 600N force is 600N / 50kg = 12 m/s^2.
What is the acceleration of a 10 kg rock that is pulled with a net force of 80N?
The acceleration of the rock can be calculated using Newton's second law, which states that acceleration is equal to the net force divided by the mass of the object. In this case, the acceleration of the 10 kg rock pulled with a net force of 80N would be 8 m/s^2.
What is the acceleration of a 7 kg mass being pulled by a 56 newton force?
The acceleration of the 7 kg mass being pulled by a 56 N force can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma). Rearranging the formula, acceleration (a) = force (F) / mass (m). Plugging in the values, we get acceleration = 56 N / 7 kg = 8 m/s^2.
What is the acceleration of a 38 kg block of cement when pulled sideways with a net force of 245 N?
If, somehow miraculously, the block is on a frictionless slide, and there isno frictional force opposing its horizontal motion, thenF = M AA = F/M = 583/44 = 13.25 m/s2 = about 1.35 G's
A block has acceleration A when pulled by a string If two identical blocks are glued together and pulled with twice the original force what will their acceleration be?
I think so. I'm not a physics expert but see if this makes sense to you.Force = mass * accelerationdouble the mass and you getForce = 2 * mass * accelerationdouble the force with double the mass and you get2 * Force = 2 * mass * accelerationusing simple division math you cancel the 2's which results inForce = mass * accelerationSo I think it would be the same acceleration.
A cart of mass 10kg pulled along a smooth platform by a force of 60N. What is the acceleration of the cart?
F=mass * acceleration 60kg m/s^2=10kg * acceleration 6m/s^2 = acceleration
What is the acceleration of a rock that has a mass of 12.2 kg and is being pulled downward with a force of 26.0?
acceleration = force/mass, so the acceleration of the rock would be equal to26/12.2, which is about 2.13 m/s2.Notise that the direction doesn't matter. The acceleration is always 2.13 m/s2,and it's always in the same direction as the force.
What is the acceleration of a 37kg block when pulled by a force of 170 N?
Using the equation F = ma, where F is the force applied (170 N), m is the mass of the block (37 kg), and a is the acceleration, we can solve for a. Rearranging the equation gives a = F/m = 170 N / 37 kg ≈ 4.59 m/s^2. Hence, the acceleration of the 37 kg block when pulled by a force of 170 N is approximately 4.59 m/s^2.
If a car were being moved sideways could you determine the force on the car by using the weight equation?
No, the weight equation only accounts for the gravitational force acting vertically on an object. To determine the force on a car being moved sideways, you would need to consider additional factors such as friction, acceleration, and the angle of the inclined plane if applicable.
What do you think will happen to the cart's acceleration when it is pulled with a constant net force?
The cart's acceleration will be directly proportional to the net force applied to it. If the force remains constant, the acceleration will also remain constant, assuming no other external factors are affecting the cart's motion.
What force will a 50 kilogram object have as it is pulled towards the earth?
The mass of the object is 50 kilogram. The acceleration due to gravity on earth is 9.8m/s2. So the force experienced by the object will be F=mass * acceleration =50*9.8 =490N
